Simplest way to increment a date in PHP?
Solution 1
A clean way is to use strtotime()
$date = strtotime("+1 day", strtotime("2007-02-28"));
echo date("Y-m-d", $date);
Will give you the 2007-03-01
Solution 2
It's cleaner and simpler to add 86400. :)
The high-tech way is to do:
$date = new DateTime($input_date);
$date->modify('+1 day');
echo $date->format('Y-m-d');
but that's really only remotely worthwhile if you're doing, say, a sequence of transformations on the date, rather than just finding tomorrow.
Solution 3
You can do the addition right inside strtotime, e.g.
$today="2007-02-28";
$nextday=strftime("%Y-%m-%d", strtotime("$today +1 day"));
Solution 4
Another way is to use function mktime(). It is very useful function...
$date = "2007-02-28";
list($y,$m,$d)=explode('-',$date);
$date2 = Date("Y-m-d", mktime(0,0,0,$m,$d+1,$y));
but I think strtotime()
is better in that situation...
Solution 5
The simplest way...
echo date('Y-m-d',strtotime("+1 day")); //from today
OR from specified date...
echo date('Y-m-d',strtotime("+1 day", strtotime('2007-02-28')));
Comments
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davr almost 2 years
Say I have a string coming in,
"2007-02-28"
, what's the simplest code I could write to turn that into"2007-03-01"
? Right now I'm just usingstrtotime()
, then adding24*60*60
, then usingdate()
, but just wondering if there is a cleaner, simpler, or more clever way of doing it. -
davr about 15 yearsStupid CentOS only has PHP 5.1, and DateTime is introduced in 5.2. I guess I finally have to upgrade to an unofficial centos php package then.
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chaos about 15 yearsOh, neat. Didn't know that. It's almost like good old Date::Manip.
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Deva about 15 yearsEr, no. Just adding 86400 is false simplicity.
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chaos about 15 yearsCould you explain what you mean by that?
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Tom Haigh about 15 yearsIt is quite easy to understand what 24*60*60 means at a glance. 86400 less so.
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Tom Haigh about 15 yearsnice, I didn't realise that mktime() would increment the month like that when you go over
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chaos about 15 yearsAh. I guess I've been doing this too long, then. 86400 is as recognizable to me as 65536.
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Deva about 15 years@chaos: If your smallest unit of working time is a day, then you can usually get away with adding or substracting units of 86400. If it is smaller, you need to be aware of daylight savings and time zones. In which case, use the built-in functions. They will get it right more often than you will.
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Jimmy T. over 7 yearsNot all days are 86400 seconds long (leap seconds).
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Eatsleeprace Livelife over 6 years/("1month")= will increment by month. //("1day")= will increment by day. //(date("Y-m-d"))=start to increment date on you current date.
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astidham2003 over 6 yearsYou should edit your answer to include the explanation of the code, instead of having the explanation in a comment.