determine if date is beyond 90 days in bash
8,959
Solution 1
You can use GNU date
to convert a date-time string into a number of seconds (since "the epoch", 1st January 1970). From there it's a simple arithmetic comparison
datetime='2016-08-31T15:38:18Z'
timeago='90 days ago'
dtSec=$(date --date "$datetime" +'%s') # For "now", use $(date +'%s')
taSec=$(date --date "$timeago" +'%s')
echo "INFO: dtSec=$dtSec, taSec=$taSec" >&2
[ $dtSec -lt $taSec ] && echo too old
Solution 2
The below script will read the format you presented above, but if you already have the values in existing variables, you could consolidate the code:
#!/bin/bash
cutoff=$(date -d '90 days ago' +%s)
while read -r key colon date
do
age=$(date -d "$date" +%s)
if (($age < $cutoff))
then
printf "Warning! key %s is older than 90 days\n" "$key" >&2
fi
done < input
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Author by
user99201
Updated on September 18, 2022Comments
-
user99201 almost 2 years
I need to fire off an alert to the security team if a users AWS access keys exceed 90 days old. I am doing this in bash.
So far my script is outputting the keys and the dates like this:
AKIAJS7KPHZCQRQ5FJWA : 2016-08-31T15:38:18Z AKIAICDOHVTMEAB6RM5Q : 2018-02-08T03:55:51Z
How do I handle determining if the date is past 90 days old using that date format in bash?
I am using Ubuntu 18.04. I believe that the date format is ISO 8601. Please confirm/correct if that is wrong as well.