Drop partitions older than 2 months

Question

I have a table with partition based on date field. Now, I have to write a procedure to drop all partitions older than 2 months i.e. test_date is older than 2 months. How do I do it?

create table test_table
(
test_id number,
test_date date,
constraint pk_test primary key (test_id)
)
partition by range (test_date)
(
PARTITION pt01122012 VALUES LESS THAN (TO_DATE('01-DEC-
2012', 'DD-MON-YYYY')),
PARTITION pt01022013 VALUES LESS THAN (TO_DATE('01-FEB-
2013', 'DD-MON-YYYY')),
PARTITION pt01042013 VALUES LESS THAN (TO_DATE('01-APR-
2013', 'DD-MON-YYYY')),
PARTITION pt01062013 VALUES LESS THAN (TO_DATE('01-JUN-
2013', 'DD-MON-YYYY')),
PARTITION pt01082013 VALUES LESS THAN (TO_DATE('01-AUG-
2013', 'DD-MON-YYYY'))
);

Thanks in advance...

Solution

First, I'd like to point that partitioning is an advanced subject in Oracle, therefore you may want to run all DDL manually at the beginning, until you're confident enough with running DDL scripts. I would also advise you to never run a script found on the internet without having both understanding it and testing it thoroughly, especially DDL scripts.

Now for the matter at hand, you can query the *_TAB_PARTITIONS dictionary view to retrieve the partition boundary:

SQL> SELECT partition_name, high_value
  2    FROM user_tab_partitions
  3   WHERE table_name = 'TEST_TABLE';

PARTITION_NAME  HIGH_VALUE
--------------- --------------------------------------------------------
PT01122012      TO_DATE(' 2012-12-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS'
PT01022013      TO_DATE(' 2013-02-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS'
PT01042013      TO_DATE(' 2013-04-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS'
PT01062013      TO_DATE(' 2013-06-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS'
PT01082013      TO_DATE(' 2013-08-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS'

This column is of type LONG (=deprecated LOB) so we have few tools to filter with SQL, we'll have to use PL/SQL.

SQL> BEGIN
  2     FOR cc IN (SELECT partition_name, high_value --
  3                  FROM user_tab_partitions
  4                 WHERE table_name = 'TEST_TABLE') LOOP
  5        EXECUTE IMMEDIATE
  6           'BEGIN
  7               IF sysdate >= ADD_MONTHS(' || cc.high_value || ', 2) THEN
  8                  EXECUTE IMMEDIATE
  9                     ''ALTER TABLE TEST_TABLE DROP PARTITION '
 10                     || cc.partition_name || '
 11                     '';
 12               END IF;
 13            END;';
 14     END LOOP;
 15  END;
 16  /

PL/SQL procedure successfully completed

SQL> SELECT partition_name, high_value
  2    FROM user_tab_partitions
  3   WHERE table_name = 'TEST_TABLE';

PARTITION_NAME  HIGH_VALUE
--------------- -----------------------------------------------------------
PT01022013      TO_DATE(' 2013-02-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 
PT01042013      TO_DATE(' 2013-04-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 
PT01062013      TO_DATE(' 2013-06-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 
PT01082013      TO_DATE(' 2013-08-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 

Comments

[TomJava]

Can u please suggest any other ways for deleting this other that procedural approach?

[TomJava]

What will happen to the primary keys present in the table?

[Nicolas de Fontenay]

@TomJava I know it's late but for others coming later: This is the best way other than manual. You will want to add the update indexes statement so that it's rebuilt as a result of the partition drop. If you have an IOT partitioned, use "update global indexes"