Echo checked if checkbox is checked

Question

if this is my checkbox

<input type="checkbox" name="Filter[]" value="Steak" id="Filter"/>

and if checkbox is checked var_export returns me

["Filter"]=> array(1) { [0]=> string(7) "Steak" 

how do I echo "checked=checked" if checkbox is checked?

Solution 1

$checked = in_array('Steak',$_POST['Filter']) ? ' checked="checked"' : '';
echo '<input type="checkbox" name="Filter[]" value="Steak" id="Filter"'.$checked.'/>';

Solution 2

What you need is in_array(), this will check whether that value exists in the array, if your array contains the value, the function will return true and you can simply echo out the checked attribute

if (in_array('YOUR_VALUE_HERE', $arr)) {
   echo 'checked="checked"';
}

You can also make a function passing value and array as parameter and returning the value from the function.

Comments

[user2635574]

function.in-array]: Wrong datatype for second argument. what i did wrong?

[Mr. Alien]

@user2635574 you are not passing array at $arr parameter, you need to use your actual array at the place of $arr

[kejo]

@Mr.Alien, this answer works great if the checkbox is actually checked. If the checkbox is not checked an error occurs "Warning: in_array() expects parameter 2 to be array, null". Do you know how to correct this error if the checkboxes are left empty? Thanks.