Find and replace words/lines in a file

213,459

Solution 1

Any decent text editor has a search&replace facility that supports regular expressions.

If however, you have reason to reinvent the wheel in Java, you can do:

Path path = Paths.get("test.txt");
Charset charset = StandardCharsets.UTF_8;

String content = new String(Files.readAllBytes(path), charset);
content = content.replaceAll("foo", "bar");
Files.write(path, content.getBytes(charset));

This only works for Java 7 or newer. If you are stuck on an older Java, you can do:

String content = IOUtils.toString(new FileInputStream(myfile), myencoding);
content = content.replaceAll(myPattern, myReplacement);
IOUtils.write(content, new FileOutputStream(myfile), myencoding);

In this case, you'll need to add error handling and close the streams after you are done with them.

IOUtils is documented at http://commons.apache.org/proper/commons-io/javadocs/api-release/org/apache/commons/io/IOUtils.html

Solution 2

After visiting this question and noting the initial concerns of the chosen solution, I figured I'd contribute this one for those not using Java 7 which uses FileUtils instead of IOUtils from Apache Commons. The advantage here is that the readFileToString and the writeStringToFile handle the issue of closing the files for you automatically. (writeStringToFile doesn't document it but you can read the source). Hopefully this recipe simplifies things for anyone new coming to this problem.

  try {
     String content = FileUtils.readFileToString(new File("InputFile"), "UTF-8");
     content = content.replaceAll("toReplace", "replacementString");
     File tempFile = new File("OutputFile");
     FileUtils.writeStringToFile(tempFile, content, "UTF-8");
  } catch (IOException e) {
     //Simple exception handling, replace with what's necessary for your use case!
     throw new RuntimeException("Generating file failed", e);
  }

Solution 3

public static void replaceFileString(String old, String new) throws IOException {
    String fileName = Settings.getValue("fileDirectory");
    FileInputStream fis = new FileInputStream(fileName);
    String content = IOUtils.toString(fis, Charset.defaultCharset());
    content = content.replaceAll(old, new);
    FileOutputStream fos = new FileOutputStream(fileName);
    IOUtils.write(content, new FileOutputStream(fileName), Charset.defaultCharset());
    fis.close();
    fos.close();
}

above is my implementation of Meriton's example that works for me. The fileName is the directory (ie. D:\utilities\settings.txt). I'm not sure what character set should be used, but I ran this code on a Windows XP machine just now and it did the trick without doing that temporary file creation and renaming stuff.

Solution 4

You might want to use Scanner to parse through and find the specific sections you want to modify. There's also Split and StringTokenizer that may work, but at the level you're working at Scanner might be what's needed.

Here's some additional info on what the difference is between them: Scanner vs. StringTokenizer vs. String.Split

Solution 5

This is the sort of thing I'd normally use a scripting language for. It's very useful to have the ability to perform these sorts of transformations very simply using something like Ruby/Perl/Python (insert your favorite scripting language here).

I wouldn't normally use Java for this since it's too heavyweight in terms of development cycle/typing etc.

Note that if you want to be particular in manipulating XML, it's advisable to read the file as XML and manipulate it as such (the above scripting languages have very useful and simple APIs for doing this sort of work). A simple text search/replace can invalidate your file in terms of character encoding etc. As always, it depends on the complexity of your search/replace requirements.

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user459811
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user459811

Updated on June 20, 2020

Comments

  • user459811
    user459811 about 4 years

    I have a file (more specifically, a log4j configuration file) and I want to be able to read in the file and pick out certain lines in the code and replace them. For example, within the file there is a string of text that indicates the directory it is stored in, or the level of the logger. I want to be able to replace those string of text without reading in the file, writing it to another file, and deleting the original file. Is there a more efficient way of doing find and replace texts in a file using Java?

    Here is an example of the text file I'm trying to work with:

    log4j.rootLogger=DEBUG, A0
    
    log4j.appender.A0=org.apache.log4j.RollingFileAppender
    log4j.appender.A0.File=C:/log.txt
    log4j.appender.A0.MaxFileSize=100KB
    log4j.appender.A0.MaxBackupIndex=1
    
    log4j.appender.A0.layout=org.apache.log4j.RollingFileAppender
    log4j.appender.A0.layout.ConversionPattern=%-4r [%t] %-5p: %c %x - %m%n
    

    I want to be able to read the file and replace 'DEBUG' with another level or replace the file directory name 'C:/log.txt'. The log configuration file is also written in xml. An example of that is featured below.

    <?xml version="1.0" encoding="UTF-8" standalone="no"?>
    <!DOCTYPE log4j:configuration SYSTEM "log4j.dtd">
    <log4j:configuration>
        <appender class="org.apache.log4j.RollingFileAppender" name="A0">
            <param name="append" value="false"/>
            <param name="File" value="C:/log/.txt"/>
            <param name="MaxBackupIndex" value="1"/>
            <param name="MaxFileSize" value="100KB"/>
            <layout class="org.apache.log4j.PatternLayout">
                <param name="ConversionPattern" value="%-4r [%t] %-5p: %c %x - %m%n"/>
            </layout>
        </appender>
        <root>
            <level value="DEBUG"/>
            <appender-ref ref="A0"/>
        </root>
    </log4j:configuration>
    

    I'm thinking it may be possible to use a hash map for this type of implementation?