finding elements in an array using a function c++

Question

I am new to C++ and have just started learning functions. I have made a program to search an element in a 1-d array using a function search. But there is a logical error I can't comprehend! Is it because of the way the function is declared ?

int pos;    
using namespace std;

int search(int *a, int size, int num);

int search(int *a, int size, int num)  
{      
    int i;    
    for(i=0; i<size; i++)    
    {    
        if(a[i]==num)    
        {
            pos=i; return 1;
        }
        else
            return 0;
    }
}

int main()
{  
    int a[5], size, num, i;    
    system("cls");    
    cout<<"Enter size(<5) \n";
    cin>>size;
    cout<<"Enter the elements of the array \n";
    for(i=0; i<size; i++)
        cin>>a[i];
    cout<<"Enter the number to be searched \n";
    cin>>num;
    int b = search( a, size, num);
    if(b==0)
    {
        cout<<"Element not found!"; exit(0);
    }
    else
        cout<<"Element found at position "<<(pos+1);
    system("pause");
    return 0;
}

Output:

Enter size(<5)

4

Enter the elements of the array

4

3

2

1

Enter element to be searched

4

Element not found!

Solution

Your function always returns in the first loop iteration. If the first element is not the one to be searched, 0 is returned immediately. The loop never enters the second iteration.