finding the distance between a set of points using scipy.spatial.distance.cdist(X, Y) in python
Two solutions:
calculate the complete matrix directly, and the access the q-th column for the values between A and B[q].
d = scipy.spatial.distance.cdist(A,B)
for q in range(len(B)):
y = d[:,q]
print y
If the resulting matrix is too big to hold in memory. You could do this.
for q in range(len(B)):
y = scipy.spatial.distance.cdist(A,[B[q]])
print y
user3287841
Updated on November 25, 2022Comments
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user3287841 over 1 year
I have an array of data, called A that looks something like:
array([[0.59, 1.23], [0.89, 1.67], [0.21,0.99]...])
and has about 400 sets of [x,y] points in it. I want to find the distance between every set of points in A to each sets of points in B, which is another array which looks exactly the same as A but is half the length (So about 200 sets of[x,y] points). So if I wanted to find the distance between the q-th pair of [x,y] values in B against all [x,y] values in A, I've tried doing something along the lines of
import scipy.spatial.distance for q in range(0,len(B)): y=scipy.spatial.distance.cdist(A,B[:q,:])
but I don't think this is working. I just want an output that shows the distance between the q-th row of B against all points in A.
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M4rtini about 10 yearsIs the resulting matrix too big if you calculate
cdist(A,B)
and then takey[:,q]
for the distances for q-th item of B? -
user3287841 about 10 yearsthat's perfect, thanks! If you want to post as an official answer than I can mark the question as answered :)
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Farid Alijani about 4 yearsWhich of the two solutions has less computation time?