Flask app route for paths that start with X

Question

I am a beginner with Flask and python. I want to create a handler function for paths that start with "/favicon". For example the following should be handled:

• /favicon
• /faviconFOO
• /favicon_bar
• /favicon/buzz
• /favicon1337

The following should not be handled:

• /favico
• /favicoN
• /whatever

If Flask supporeted wildcards, it would be "/favicon*"

EDIT: I don't need support for regular expressions.

How can I do this?

Solution

I would do a catch-all url and then, try to use a wildcard with it from inside the view:

@app.route('/<path:text>', methods=['GET', 'POST'])
def all_routes(text):
    if text.startswith('favicon'):
        #do stuff
    else:
        return redirect(url_for('404_error'))

you can use string too:

@app.route('/<string:text>', methods=['GET'])

but using string wouldn't catch / strings. so if string is used, url's containing something like favicon/buzz wouldn't be cached by it, path in the other hand would catch /'s too. so you should go with first option.

you can look at routing documentation in flask site. and you should create a better conditional than if x in Y because it will fail if you were passed something like /thingfavicon

Comments

[ZdaR]

You want all routes: favicon, faviconFOO, favicon_bar etc. to point same handle, then you may look at this thread

[Lennart Rolland]

Yes exactly. If it was a wildcard it would be /favicon*

[Lennart Rolland]

I would not say it's a duplicate because it is much more spesific than the other question. Besides, I don't care if it is solved using regex or not.

[ZdaR]

It can be perfectly solved with regex, I guess it would be the best way to reduce redundancy in this case(flask). However Django framework has more convenient support for regexs'.

[senaps]

please let me know if the answer did what you wanted if you found another way to do it.