Given Letter, Get Next Letter in Alphabet

18,469

Solution 1

Use ASCII to get the value of the character, add one, and use CHAR to convert the value back to a character.

SELECT CHAR(ASCII('a') + 1)

Solution 2

This is how you'd do it for one letter

DECLARE @myletter char(1) = 'a';
SELECT CHAR(ASCII(@myletter)+1);

Solution 3

3 letters alfabetic counter with two SQL procedures

(a, b...z, aa, ab...zy, zz, aaa...zzz):

SET QUOTED_IDENTIFIER OFF
GO
SET ANSI_NULLS ON
GO

alter procedure letraMas
@letraEntra as char( 1),
@letraSale as char( 1) OUTPUT,
@seLleva as bit  OUTPUT

as

--set @letraEntra = 'w'
--set @letraSale = 'm'
set @seLleva = 0

select
@letraSale = CASE
        WHEN @letraEntra = '' or (@letraEntra is null) or @letraEntra = 'z'
        THEN 'a'
    WHEN @letraEntra < 'z'
        THEN CHAR (ASCII( @letraEntra) + 1)
end

if @letraEntra = 'z' set @seLleva = 1

return

SET QUOTED_IDENTIFIER OFF
GO
SET ANSI_NULLS ON
GO

/* USO:
declare
@tareaEntra as char(3),
@tareaSale as char(3)
set @tareaEntra = 'xzz'
       EXEC tareaMas @tareaEntra, @tareaSale OUTPUT
*/
alter procedure tareaMas
@tareaEntra as char( 3),
@tareaSale as char( 3) OUTPUT

as
declare @charU as char(1 )     -- char de U_nidades albabéticas
declare @charD as char(1 )     -- char de D_ecenas albabéticas
declare @charC as char(1 )     -- char de C_entenas albabéticas
declare @letraSale as char(1 )        -- char de C_entenas albabéticas
declare @seLleva as bit

set @tareaEntra   = right('   ' + rtrim (@tareaEntra), 3)

set @charU = substring(@tareaEntra , 3, 1)
set @charD = substring(@tareaEntra , 2, 1)
set @charC = substring(@tareaEntra , 1, 1)

EXEC letraMas @charU, @letraSale OUTPUT, @seLleva OUTPUT
set @charU = @letraSale
if @seLleva = 1
BEGIN
        EXEC letraMas @charD, @letraSale OUTPUT, @seLleva OUTPUT
        set @charD = @letraSale
        if @seLleva = 1
        BEGIN
               EXEC letraMas @charC, @letraSale OUTPUT, @seLleva OUTPUT
               set @charC = @letraSale
        END
END

set @tareaSale = ltrim(@charC + @charD + @charU)
return

Solution 4

Here is a CTE with Jonathan Wood's implementation

;WITH cte AS
   (SELECT  CHAR(ASCII('a')) [char], 1 [count]
    UNION ALL
    SELECT  CHAR(ASCII('a') + cte.count) [char], cte.count + 1 [count]
    FROM    cte)
SELECT  TOP(26) cte.count[pos], cte.char
FROM    cte

you can either use it just like that or insert the results into a table variable or temporary table and use it on that.

Another tip I would also give is, have a table in your database with this cte's data, then it is easier in the future to join to it and use it like that for whatever purpose or reason.

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18,469
Lloyd Banks
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Lloyd Banks

Updated on June 12, 2022

Comments

  • Lloyd Banks
    Lloyd Banks about 2 years

    I have letter "a", "b", "c". I would like my results to be "b", "c", "d" in TSQL respectively. Would what I use to achieve this?