hierarchical clustering on correlations in Python scipy/numpy?

12,353

Just change the metric to correlation so that the first line becomes:

Y=pdist(X, 'correlation')

However, I believe that the code can be simplified to just:

Z=linkage(X, 'single', 'correlation')
dendrogram(Z, color_threshold=0)

because linkage will take care of the pdist for you.

Share:
12,353
Admin
Author by

Admin

Updated on June 05, 2022

Comments

  • Admin
    Admin almost 2 years

    How can I run hierarchical clustering on a correlation matrix in scipy/numpy? I have a matrix of 100 rows by 9 columns, and I'd like to hierarchically cluster by correlations of each entry across the 9 conditions. I'd like to use 1-pearson correlation as the distances for clustering. Assuming I have a numpy array X that contains the 100 x 9 matrix, how can I do this?

    I tried using hcluster, based on this example:

    Y=pdist(X, 'seuclidean')
    Z=linkage(Y, 'single')
    dendrogram(Z, color_threshold=0)
    

    However, pdist is not what I want, since that's a euclidean distance. Any ideas?

    thanks.

  • Admin
    Admin almost 14 years
    Does 'correlation' here mean Pearson or Spearman? Also, shouldn't it be 1 - pearson in order to be a valid distance metric that can be used for pdist? Does pdist do that automatically? thanks.
  • Justin Peel
    Justin Peel almost 14 years
    It looks like it is 1 - pearson to me. You can look at it yourself in site-packages/scipy/spatial/distance.py
  • dwf
    dwf almost 14 years
    It's fairly rare for "correlation" mentioned alone to mean Spearman correlation. Usually if it's Spearman people will say so, otherwise assume Pearson.