How can I return pivot table output in MySQL?
Solution 1
This basically is a pivot table.
A nice tutorial on how to achieve this can be found here: http://www.artfulsoftware.com/infotree/qrytip.php?id=78
I advise reading this post and adapt this solution to your needs.
Update
After the link above is currently not available any longer I feel obliged to provide some additional information for all of you searching for mysql pivot answers in here. It really had a vast amount of information, and I won't put everything from there in here (even more since I just don't want to copy their vast knowledge), but I'll give some advice on how to deal with pivot tables the sql way generally with the example from peku who asked the question in the first place.
Maybe the link comes back soon, I'll keep an eye out for it.
The spreadsheet way...
Many people just use a tool like MSExcel, OpenOffice or other spreadsheet-tools for this purpose. This is a valid solution, just copy the data over there and use the tools the GUI offer to solve this.
But... this wasn't the question, and it might even lead to some disadvantages, like how to get the data into the spreadsheet, problematic scaling and so on.
The SQL way...
Given his table looks something like this:
CREATE TABLE `test_pivot` (
`pid` bigint(20) NOT NULL AUTO_INCREMENT,
`company_name` varchar(32) DEFAULT NULL,
`action` varchar(16) DEFAULT NULL,
`pagecount` bigint(20) DEFAULT NULL,
PRIMARY KEY (`pid`)
) ENGINE=MyISAM;
Now look into his/her desired table:
company_name EMAIL PRINT 1 pages PRINT 2 pages PRINT 3 pages
-------------------------------------------------------------
CompanyA 0 0 1 3
CompanyB 1 1 2 0
The rows (EMAIL, PRINT x pages) resemble conditions. The main grouping is by company_name.
In order to set up the conditions this rather shouts for using the CASE-statement. In order to group by something, well, use ... GROUP BY.
The basic SQL providing this pivot can look something like this:
SELECT P.`company_name`,
COUNT(
CASE
WHEN P.`action`='EMAIL'
THEN 1
ELSE NULL
END
) AS 'EMAIL',
COUNT(
CASE
WHEN P.`action`='PRINT' AND P.`pagecount` = '1'
THEN P.`pagecount`
ELSE NULL
END
) AS 'PRINT 1 pages',
COUNT(
CASE
WHEN P.`action`='PRINT' AND P.`pagecount` = '2'
THEN P.`pagecount`
ELSE NULL
END
) AS 'PRINT 2 pages',
COUNT(
CASE
WHEN P.`action`='PRINT' AND P.`pagecount` = '3'
THEN P.`pagecount`
ELSE NULL
END
) AS 'PRINT 3 pages'
FROM test_pivot P
GROUP BY P.`company_name`;
This should provide the desired result very fast. The major downside for this approach, the more rows you want in your pivot table, the more conditions you need to define in your SQL statement.
This can be dealt with, too, therefore people tend to use prepared statements, routines, counters and such.
Some additional links about this topic:
- http://anothermysqldba.blogspot.de/2013/06/pivot-tables-example-in-mysql.html
- http://www.codeproject.com/Articles/363339/Cross-Tabulation-Pivot-Tables-with-MySQL
- http://datacharmer.org/downloads/pivot_tables_mysql_5.pdf
- https://codingsight.com/pivot-tables-in-mysql/
Solution 2
My solution is in T-SQL without any pivots:
SELECT
CompanyName,
SUM(CASE WHEN (action='EMAIL') THEN 1 ELSE 0 END) AS Email,
SUM(CASE WHEN (action='PRINT' AND pagecount=1) THEN 1 ELSE 0 END) AS Print1Pages,
SUM(CASE WHEN (action='PRINT' AND pagecount=2) THEN 1 ELSE 0 END) AS Print2Pages,
SUM(CASE WHEN (action='PRINT' AND pagecount=3) THEN 1 ELSE 0 END) AS Print3Pages
FROM
Company
GROUP BY
CompanyName
Solution 3
For MySQL you can directly put conditions in SUM() function and it will be evaluated as Boolean 0 or 1 and thus you can have your count based on your criteria without using IF/CASE statements
SELECT
company_name,
SUM(action = 'EMAIL')AS Email,
SUM(action = 'PRINT' AND pagecount = 1)AS Print1Pages,
SUM(action = 'PRINT' AND pagecount = 2)AS Print2Pages,
SUM(action = 'PRINT' AND pagecount = 3)AS Print3Pages
FROM t
GROUP BY company_name
DEMO
Solution 4
For dynamic pivot, use GROUP_CONCAT with CONCAT.
The GROUP_CONCAT function concatenates strings from a group into one string with various options.
SET @sql = NULL;
SELECT
GROUP_CONCAT(DISTINCT
CONCAT(
'SUM(CASE WHEN action = "',
action,'" AND ',
(CASE WHEN pagecount IS NOT NULL
THEN CONCAT("pagecount = ",pagecount)
ELSE pagecount IS NULL END),
' THEN 1 ELSE 0 end) AS ',
action, IFNULL(pagecount,'')
)
)
INTO @sql
FROM
t;
SET @sql = CONCAT('SELECT company_name, ', @sql, '
FROM t
GROUP BY company_name');
PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
Solution 5
A stardard-SQL version using boolean logic:
SELECT company_name
, COUNT(action = 'EMAIL' OR NULL) AS "Email"
, COUNT(action = 'PRINT' AND pagecount = 1 OR NULL) AS "Print 1 pages"
, COUNT(action = 'PRINT' AND pagecount = 2 OR NULL) AS "Print 2 pages"
, COUNT(action = 'PRINT' AND pagecount = 3 OR NULL) AS "Print 3 pages"
FROM tbl
GROUP BY company_name;
How?
TRUE OR NULL yields TRUE.
FALSE OR NULL yields NULL.
NULL OR NULL yields NULL.
And COUNT only counts non-null values. Voilá.
peku
Updated on July 08, 2022Comments
-
peku almost 2 years
If I have a MySQL table looking something like this:
company_name action pagecount ------------------------------- Company A PRINT 3 Company A PRINT 2 Company A PRINT 3 Company B EMAIL Company B PRINT 2 Company B PRINT 2 Company B PRINT 1 Company A PRINT 3
Is it possible to run a MySQL query to get output like this:
company_name EMAIL PRINT 1 pages PRINT 2 pages PRINT 3 pages ------------------------------------------------------------- CompanyA 0 0 1 3 CompanyB 1 1 2 0
The idea is that
pagecountcan vary so the output column amount should reflect that, one column for eachaction/pagecountpair and then number of hits percompany_name. I'm not sure if this is called a pivot table but someone suggested that?