How do I compare a string and an integer in Python?

14,634

Solution 1

You should do:

user_input = int(input('How old are you?: '))

so as you explicitly cast your input as int, it will always try to convert the input into an integer, and will raise a valueError when you enter a string rather than an int. To handle those cases, do:

except ValueError:
    print ('That is not a number')

So, the full solution might be like below:

try:
    user_input = int(input('How old are you?: '))

    if user_input >= 18:
         print('You are an adult')
    else:
         print('You are quite young')
except ValueError:
    print ('That is not a number')

Solution 2

user_input is a str, you're comparing it to an int. Python does not know how to do that. You will need to convert one of them to the other type to get a proper comparison.

For example, you can convert a string to an integer with the int() function:

user_input = int(input('How old are you?: '))
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Keretto
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Keretto

Updated on June 07, 2022

Comments

  • Keretto
    Keretto almost 2 years

    I am quite a newbie in Python. I wrote this and got this error when i typed a letter in the input:

    TypeError: unorderable types: str() >= int()
    

    Here is the code that I wrote:

    user_input = input('How old are you?: ')
    if user_input >= 18:
       print('You are an adult')
    elif user_input < 18:
         print('You are quite young')
    elif user_input == str():
         print ('That is not a number')