How do I compare a string and an integer in Python?
14,634
Solution 1
You should do:
user_input = int(input('How old are you?: '))
so as you explicitly cast your input as int, it will always try to convert the input into an integer, and will raise a valueError when you enter a string rather than an int. To handle those cases, do:
except ValueError:
print ('That is not a number')
So, the full solution might be like below:
try:
user_input = int(input('How old are you?: '))
if user_input >= 18:
print('You are an adult')
else:
print('You are quite young')
except ValueError:
print ('That is not a number')
Solution 2
user_input
is a str
, you're comparing it to an int
. Python does not know how to do that. You will need to convert one of them to the other type to get a proper comparison.
For example, you can convert a string to an integer with the int()
function:
user_input = int(input('How old are you?: '))
Author by
Keretto
Updated on June 07, 2022Comments
-
Keretto almost 2 years
I am quite a newbie in Python. I wrote this and got this error when i typed a letter in the input:
TypeError: unorderable types: str() >= int()
Here is the code that I wrote:
user_input = input('How old are you?: ') if user_input >= 18: print('You are an adult') elif user_input < 18: print('You are quite young') elif user_input == str(): print ('That is not a number')