How do I copy with scp with a wildcard(*) in the destination path?

12,084

Solution 1

It depends on whether you want to expand * before running a command or after running it and whether you want to do it interactively or not.

If you want to expand it before running a command interactively you can either use insert-completions (M-*) or glob-expand-word (C-x *) described in man bash:

   glob-expand-word (C-x *)
          The word before point is treated as a pattern for
          pathname expansion, and the list of matching filenames
          is inserted, replacing the word.  If a numeric argument
          is sup- plied, an asterisk is appended before pathname
          expansion.

   insert-completions (M-*)
          Insert all completions of the text before point that
          would have been generated by possible-completions.

To use these functions put a cursor before or after * and press either Control-x * or Alt-*:

$ pwd
/tmp/expand-glob
$ ls
FILE
$ cp /tmp/expand-*/*

Now put your cursor after the last *, don't press Enter but C-x * and you'll get this

$ cp /tmp/expand-glob/FILE

If you want to expand * to test command in the script then neither scp nor cp is a good option because the cannot run in dry-run mode. You should go with something like rsync that would show what files it would transfer if it was actually run like this:

$ rsync  -vn --relative /tmp/expand-*/* .
/tmp/
/tmp/expand-scp/
/tmp/expand-scp/a
/tmp/expand-scp/b
/tmp/expand-scp/c
/tmp/expand-scp/mmmm32

EDIT:

How about this:

$ rsync -avn -R --rsync-path="cd sixtrack/simulations && rsync"  user@host:run*/summary.dat .

-n stands for dry-run. With this option rsync will only print how will recreate a remote directory structure in current directory. In your case it will be something like:

receiving incremental file list
drwxr-xr-x          4,096 2016/10/13 12:45:36 run0001
-rw-r--r--              0 2016/10/13 12:23:18 run0001/summary.dat
drwxr-xr-x          4,096 2016/10/13 12:23:18 run00010
-rw-r--r--              0 2016/10/13 12:23:18 run00010/summary.dat
drwxr-xr-x          4,096 2016/10/13 12:23:18 run0002
-rw-r--r--              0 2016/10/13 12:23:18 run0002/summary.dat
drwxr-xr-x          4,096 2016/10/13 12:23:18 run0003
-rw-r--r--              0 2016/10/13 12:23:18 run0003/summary.dat
drwxr-xr-x          4,096 2016/10/13 12:23:18 run0004
-rw-r--r--              0 2016/10/13 12:23:18 run0004/summary.dat
drwxr-xr-x          4,096 2016/10/13 12:23:18 run0005
-rw-r--r--              0 2016/10/13 12:23:18 run0005/summary.dat
drwxr-xr-x          4,096 2016/10/13 12:23:18 run0006
-rw-r--r--              0 2016/10/13 12:23:18 run0006/summary.dat
drwxr-xr-x          4,096 2016/10/13 12:23:18 run0007
-rw-r--r--              0 2016/10/13 12:23:18 run0007/summary.dat
drwxr-xr-x          4,096 2016/10/13 12:23:18 run0008
-rw-r--r--              0 2016/10/13 12:23:18 run0008/summary.dat
drwxr-xr-x          4,096 2016/10/13 12:23:18 run0009
-rw-r--r--              0 2016/10/13 12:23:18 run0009/summary.dat

Solution 2

What you're asking for is impossible since cp/scp commands take only a single destination. However you can easily simulate it with some very straightforward scripting:

for d in *
do
    scp -r user@host:some/path/with/"$d"/file.txt cp/to/"$d"/file.txt
done

It can also be written on a single line as

for d in *; do scp -r user@host:some/path/with/"$d"/file.txt cp/to/"$d"/file.txt; done
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pingul
Author by

pingul

Applied physics/engineering graduate from Sweden. I enjoy tinkering with C++ and Python :) Some of my favourite answers and questions: A: Fill 2-dimensional array with zeros by flipping groups of cells A: Best data structure for point traversal Q: Multiple inheritance with variadic templates: how to call function for each base class?

Updated on July 10, 2022

Comments

  • pingul
    pingul almost 2 years

    Is it possible to get the value of what a wildcard matched to? I.e. I want to do

    scp -r user@host:some/path/with/*/file.txt cp/to/*/file.txt
    

    With the command above, I want

    some/path/with/TEST/file.txt --> cp/to/TEST/file.txt
    some/path/with/OTHER/file.txt --> cp/to/OTHER/file.txt
    

    EDIT: I'll add some more data of my actual setup, which might make it clearer.

    On my server I have the structure

    server $ pwd
    ~/sixtrack/simulations
    server $ ls
    run0001
    run0002
    run0003
    ...
    

    Each run* is a directory, containing files like run*/summary.dat, run*/tracks.dat etc. I could copy everything over to my own computer like

    pingul $ scp -r 'user@host:sixtrack/simulations/*' .
    

    However, I would like to not copy over every file, instead just some. Because all files are named the same and only separated through the directory, I have to respect the structure. As such, I would like host:sixtrack/simulations/run0001/summary.dat to go into my local folder /Users/pingul/Workspace/simulations/run0001/summary.dat.

    Running

    pingul $ pwd
    /Users/pingul/Workspace/simulations
    pingul $ scp -r 'user@host:sixtrack/simulations/*/summary.dat' */.
    

    Does not accomplish what I want. Adding the -v option as suggested prints out

    Executing: cp -r -- run0001/. run0100/.
    Executing: cp -r -- run0002/. run0100/.
    Executing: cp -r -- run0003/. run0100/.
    ...
    

    and I only get one summary.dat in run0100. All other directories are empty (i.e. run0001, run0002, ...)

    Is what I want possible?