How does one supply a custom sort function for react table 7?
Solution 1
The arguments for the sortType function are: (rowA, rowB, columnId, desc)
columnId
identifies which column the row is being sorted by, and so allows getting the cell value.
desc
identifies the direction of the sort. Even though desc
is supplied, the sort function should NOT reverse the return values. react table automatically does this.
For example:
sortType: React.useMemo((rowA, rowB, id, desc) => {
if (rowA.values[id] > rowB.values[id]) return 1;
if (rowB.values[id] > rowA.values[id]) return -1;
return 0;
})
example of where to use sortType:
const columns = [{
Header: ...
accessor: ...
sortType: /*sortType func goes here... */
}, ...]
function MyTable(columns, data)
{
const { /*...*/ } = useTable({columns,data})
}
Solution 2
Per your doc citation, sortType is a Column option.
The following options are supported on any
Column
object passed to thecolumns
options inuseTable()
For instance, modify the Quick Start's Define Columns, like so:
const columns = React.useMemo(
() => [
{
Header: 'Column 1',
accessor: 'col1', // accessor is the "key" in the data
},
{
Header: 'Column 2',
accessor: 'col2',
sortType: compareNumericString // custom function
},
],
[]
)
function compareNumericString(rowA, rowB, id, desc) {
let a = Number.parseFloat(rowA.values[id]);
let b = Number.parseFloat(rowB.values[id]);
if (Number.isNaN(a)) { // Blanks and non-numeric strings to bottom
a = desc ? Number.NEGATIVE_INFINITY : Number.POSITIVE_INFINITY;
}
if (Number.isNaN(b)) {
b = desc ? Number.NEGATIVE_INFINITY : Number.POSITIVE_INFINITY;
}
if (a > b) return 1;
if (a < b) return -1;
return 0;
}
Solution 3
I had quite a bit of trouble figuring this one out as well. Here's how I did it. It's in typescript, but if you need it in plain js, just remove all the typings. 1st, here' the custom sort. It will sort strings, and always put the nulls/blanks/undefined at the end.
const customStringSort: any = (rowA: Row, rowB: Row, columnId: string, desc: boolean) => {
const defaultVal = desc ? 'AAAAAAAAAAAA' : 'ZZZZZZZZ';
return (rowA.values[columnId] ?? defaultVal)
.localeCompare(rowB.values[columnId] ?? defaultVal);
};
There are 2 things to notice about this.
- I couldn't figure out why typescript didn't like it when the return was defined as a number. I hate to use any, but this works.
- The react table documentation indicates that this must be memoized. This is not, but it works still.
Next you have to add this function to the sortTypes.
const sortTypes: Record<string, SortByFn<SomeObject>> = {
customStringSort: customStringSort,
};
Next, add the sortTypes to the useTable instance.
const {
getTableProps,
getTableBodyProps
headerGroups,
rows,
prepareRow,
} = useTable(
{
columns,
data,
sortTypes
},
useSortBy
);
Now you can add the custom function into your column definitions.
const columns: Column<SomeObject>[] = React.useMemo(() =>
[
{ accessor: 'someColumnID', Header: 'Some Column', sortType:'customStringSort' },
],
[],
);
Hope this helps!
--Edit: If you want to memoized the function, this works. Just replace customStringSort with customStringSortMemo where appropriate.
const customStringSort: any = React.useCallback((rowA: Row, rowB: Row, columnId: string, desc: boolean) =>
{
const defaultVal = desc ? 'AAAAAAAAAAAA' : 'ZZZZZZZZ';
return (rowA.values[columnId] ?? defaultVal).localeCompare(rowB.values[columnId] ?? defaultVal);
},
[]);
const customStringSortMemo = React.useMemo(() => customStringSort[customStringSort]);
Tom
Updated on July 27, 2022Comments
-
Tom almost 2 years
The documention for useSortBy sortType properties says:
sortType: String | Function(rowA: <Row>, rowB: <Row>, columnId: String, desc: Bool) Used to compare 2 rows of data and order them correctly. If a function is passed, it must be memoized. The sortType function should return -1 if rowA is larger, and 1 if rowB is larger. react-table will take care of the rest. String options: basic, datetime, alphanumeric. Defaults to alphanumeric. The resolved function from the this string/function will be used to sort the this column's data. If a string is passed, the function with that name located on either the custom sortTypes option or the built-in sorting types object will be used. If a function is passed, it will be used. For more information on sort types, see Sorting
but doesn't explain fully how to use it.
So how does one supply a sortType function?
-
rook218 over 3 yearsThanks for this, but I'm not sure how you could come to that answer from the react-table docs... How do you know that rows will have an property of type object that you can access with the id property? I am also getting the error "React Hook "React.useMemo" cannot be called in a class component" since I am constructing my columns in a class component, then passing them to the presentational component that builds my table. Is there a workaround for that?
-
Eman4real over 3 yearsreact-table.tanstack.com/docs/api/useSortBy You need to pass this function to Columns. I'm still working on how to do it myself but I'll post when I come up with something. You can't use hooks in a react class component. I'd put everything that is related to react-table in functional components. All the documentation has them in the same file but I'm also trying to get some separation.
-
Kildareflare almost 3 yearsregarding TS and
any
. You have the type in the wrong place. It should be after the params. E.g.const customStringSort = (rowA: Row, rowB: Row, columnId: string, desc: boolean):number => {
-
Ken Lin almost 3 years@Tom, In your sort function above I suspect most people would use
rowA.values[id]
rather thanrowA.original[id]
. Also, the common semantics of>
might return1
rather than-1
. -
Ken Lin almost 3 years@Eman4real, no need to inline your function. Simply supply
sortType
with the name of your compare function (e.g.,compareNumericString
) as I've done here. -
superk over 2 yearsThis is great for sorting a row of scientific-formatted numbers (come back to the renderer as strings). This way we don't care if they are listed as strings or not.
-
Daniel Danielecki over 2 yearsThe only one solution, which worked out.