How to compare two NSInteger?

Question

How do we compare two NSInteger numbers ? I have two NSIntegers and comparing them the regular way wasnt working.

if (NSIntegerNumber1 >= NSIntegerNumber2) {
    //do something
}

Eventhough, the first value was 13 and the second value was 17, the if loop is executing

Any idea ?

Solution 1

NSInteger int1;
NSInteger int2;

int1 = 13;
int2 = 17;

if (int1 > int2)
{
    NSLog(@"works");
}

Solution 2

NSInteger is just a typedef for a builtin integral type (e.g. int or long).

It is safe to compare using a == b.

Other common operators behave predictably: !=, <=, <, >= et al.

Finally, NSInteger's underlying type varies by platform/architecture. It is not safe to assume it will always be 32 or 64 bit.

Solution 3

Well, since you have Integer and Number in the name, you might have declared the two values as NSNumber instead of NSInteger. If so, then you need to do the following:

 if ([NSIntegerNumber1 intValue] >= [NSIntegerNumber2 intValue]) {
      // do something
 }

Otherwise it should work as is!

Solution 4

When comparing integers, using this, would work just fine:

int a = 5;
int b = 7;

if (a < b) {

NSLog(@"%d is smaller than %d" a, b);   

}

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Comments

[Ali Saeed]

This should be voted up, as it explains the reasoning