How to convert a string to a HashMap?
Solution 1
Use the String.split()
method with the ,
separator to get the list of pairs. Iterate the pairs and use split()
again with the :
separator to get the key and value for each pair.
Map<String, Integer> myMap = new HashMap<String, Integer>();
String s = "SALES:0,SALE_PRODUCTS:1,EXPENSES:2,EXPENSES_ITEMS:3";
String[] pairs = s.split(",");
for (int i=0;i<pairs.length;i++) {
String pair = pairs[i];
String[] keyValue = pair.split(":");
myMap.put(keyValue[0], Integer.valueOf(keyValue[1]));
}
Solution 2
You can do that with Guava's Splitter.MapSplitter:
Map<String, String> properties = Splitter.on(",")
.withKeyValueSeparator(":")
.split(inputString);
Solution 3
In one line :
HashMap<String, Integer> map = (HashMap<String, Integer>) Arrays.asList(str.split(",")).stream().map(s -> s.split(":")).collect(Collectors.toMap(e -> e[0], e -> Integer.parseInt(e[1])));
Details:
1) Split entry pairs and convert string array to List<String>
in order to use java.lang.Collection.Stream
API from Java 1.8
Arrays.asList(str.split(","))
2) Map the resulting string list "key:value"
to a string array with [0] as key and [1] as value
map(s -> s.split(":"))
3) Use collect
terminal method from stream API to mutate
collect(Collector<? super String, Object, Map<Object, Object>> collector)
4) Use the Collectors.toMap()
static method which take two Function to perform mutation from input type to key and value type.
toMap(Function<? super T,? extends K> keyMapper, Function<? super T,? extends U> valueMapper)
where T is the input type, K the key type and U the value type.
5) Following lambda mutate String
to String
key and String
to Integer
value
toMap(e -> e[0], e -> Integer.parseInt(e[1]))
Enjoy the stream and lambda style with Java 8
. No more loops !
Solution 4
I recommend using com.fasterxml.jackson.databind.ObjectMapper
(Maven repo link: https://mvnrepository.com/artifact/com.fasterxml.jackson.core) like
final ObjectMapper mapper = new ObjectMapper();
Map<String, Object> mapFromString = new HashMap<>();
try {
mapFromString = mapper.readValue(theStringToParse, new TypeReference<Map<String, Object>>() {
});
} catch (IOException e) {
LOG.error("Exception launched while trying to parse String to Map.", e);
}
Solution 5
Assuming no key contains either ','
or ':'
:
Map<String, Integer> map = new HashMap<String, Integer>();
for(final String entry : s.split(",")) {
final String[] parts = entry.split(":");
assert(parts.length == 2) : "Invalid entry: " + entry;
map.put(parts[0], new Integer(parts[1]));
}
Comments
-
Bishan over 2 years
I have a Java Property file and there is a
KEY
asORDER
. So I retrieve theVALUE
of thatKEY
using thegetProperty()
method after loading the property file like below.:String s = prop.getProperty("ORDER");
then
s ="SALES:0,SALE_PRODUCTS:1,EXPENSES:2,EXPENSES_ITEMS:3";
I need to create a HashMap from above string.
SALES,SALE_PRODUCTS,EXPENSES,EXPENSES_ITEMS
should beKEY
of HashMap and0,1,2,3,
should beVALUE
s ofKEY
s.If it's hard corded, it seems like below:
Map<String, Integer> myMap = new HashMap<String, Integer>(); myMap.put("SALES", 0); myMap.put("SALE_PRODUCTS", 1); myMap.put("EXPENSES", 2); myMap.put("EXPENSES_ITEMS", 3);