How to convert date to the first day of month in a PySpark Dataframe column?
20,484
You can use trunc
:
import pyspark.sql.functions as f
df.withColumn("first_date", f.trunc("date", "month")).show()
+----------+----------+
| date|first_date|
+----------+----------+
|2017-11-25|2017-11-01|
|2017-12-21|2017-12-01|
|2017-09-12|2017-09-01|
+----------+----------+
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Rakesh Adhikesavan
I'm a science enthusiast, a technophile, a dog lover and an aspiring Data Scientist.
Updated on January 02, 2021Comments
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Rakesh Adhikesavan over 3 years
I have the following DataFrame:
+----------+ | date| +----------+ |2017-01-25| |2017-01-21| |2017-01-12| +----------+
Here is the code the create above DataFrame:
import pyspark.sql.functions as f rdd = sc.parallelize([("2017/11/25",), ("2017/12/21",), ("2017/09/12",)]) df = sqlContext.createDataFrame(rdd, ["date"]).withColumn("date", f.to_date(f.col("date"), "yyyy/MM/dd")) df.show()
I want a new column with the first date of month for each row, just replace the day to "01" in all the dates
+----------++----------+ | date| first_date| +----------++----------+ |2017-11-25| 2017-11-01| |2017-12-21| 2017-12-01| |2017-09-12| 2017-09-01| +----------+-----------+
There is a last_day function in PySpark.sql.function, however, there is no first_day function.
I tried using date_sub to do this but did not work: I get a column not Iterable error because the second argument to date_sub cannot be a column and has to be an integer.
f.date_sub(f.col('date'), f.dayofmonth(f.col('date')) - 1 )