How to convert NSTimeInterval to int?
Solution 1
Direct assignment:
NSTimeInterval interval = 1002343.5432542;
NSInteger time = interval;
//time is now equal to 1002343
NSTimeInterval is a double, so if you assign it directly to a NSInteger (or int, if you wish) it'll work. This will cut off the time to the nearest second.
If you wish to round to the nearest second (rather than have it cut off) you can use round before you make the assignment:
NSTimeInterval interval = 1002343.5432542;
NSInteger time = round(interval);
//time is now equal to 1002344
Solution 2
According to the documentation, NSTimeInterval
is just a double
:
typedef double NSTimeInterval;
You can cast this to an int
:
seconds = (int) myTimeInterval;
Watch out for overflows, though!
Solution 3
In Swift 3.0
let timestamp = round(NSDate().timeIntervalSince1970)
Solution 4
I suspect that NSTimeInterval values from NSDate would overflow an NSInteger. You'd likely want a long long. (64 bit integer.) Those can store honking-big integer values (-2^63 to 2^63 -1)
long long integerSeconds = round([NSDate timeIntervalSinceReferenceDate]);
EDIT:
It looks like an NSInteger CAN store an NSTimeInterval, at least for the next couple of decades. The current date's timeIntervalSinceReferenceDate is about 519,600,000, or about 2^28. On a 32 bit device, and NSInteger can hold a value from -2^31 to 2^31-1. (2^31 is 2,147,483,648
Solution 5
Swift 4, Swift 5
I simply cast to Int64
:
Int64(Date().timeIntervalSince1970)
![Pradeep Reddy Kypa](https://i.stack.imgur.com/jau0L.jpg?s=256&g=1)
Pradeep Reddy Kypa
iOS Architect with a relevant experience of 13+ years. I want to master iOS SDK Technologies and very much interested to learn any new stuff regarding iOS.#SOreadytohelp
Updated on May 28, 2020Comments
-
Pradeep Reddy Kypa about 4 years
How do I convert NSTimeInterval into an Integer value?
My TimeInterval holds the value
83.01837
. I need to convert it into83
. I have googled but couldn't find any help. -
Richard J. Ross III about 12 yearsPossibly want a
round()
call in there. -
Aaron Hayman about 12 yearshmmm...wouldn't it be better to just add .5 to interval? I know I'm really bickering here but the effect will be the same without using up a function call.
-
Richard J. Ross III about 12 yearsActually, round is better, seeing as it works properly with negative numbers as expected, whilst adding .5 or to the number doesn't...
-
Aaron Hayman about 12 yearsAhh true enough...pesky negatives. :)
-
HereTrix almost 8 yearsDouble() doesn't create integeg value
-
prakash over 7 yearsThis will give you with the decimal point followed by 0. (83.01837--> 83.0)
-
AP_ over 7 yearsKindly check the attached screenshot @prakash