how to count the seconds in java?

22,039

Solution 1

You can use either long values with milliseconds since epoch, or java.util.Date objects (which internally uses long values with milliseconds since epoch, but are easier to display/debug).

// Using millis
class MyObj {
    private final long createdMillis = System.currentTimeMillis();

    public int getAgeInSeconds() {
        long nowMillis = System.currentTimeMillis();
        return (int)((nowMillis - this.createdMillis) / 1000);
    }
}
// Using Date
class MyObj {
    private final Date createdDate = new java.util.Date();

    public int getAgeInSeconds() {
        java.util.Date now = new java.util.Date();
        return (int)((now.getTime() - this.createdDate.getTime()) / 1000);
    }
}

Solution 2

When you create your object call.

Date startDate = new Date();

After you are done call;

Date endDate = new Date();

The number of seconds elapsed is:

int numSeconds = (int)((endDate.getTime() - startDate.getTime()) / 1000);
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Updated on July 15, 2022

Comments

  • Admin
    Admin almost 2 years

    I'm trying to understand how I could go about keeping track of the seconds that an object has been created for.

    The program I'm working on with simulates a grocery store.

    Some of the foods posses the trait to spoil after a set amount of time and this is all done in a subclass of an item class called groceryItem. The seconds do not need to be printed but are kept track of using a currentTime field and I don't quite understand how to count the seconds exactly.

    I was looking at using the Java.util.Timer or the Java.util.Date library maybe but I don't fully understand how to use them for my issue.

    I don't really have a very good understanding of java but any help would be appreciated.