How to create a correct exit button in qt
35,878
Connect the button's clicked()
signal to your main window's close()
slot. That way things are cleaned up properly.
Comments
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Frank almost 4 years
I'm trying to create an exit button that correctly closes the GUI I have made in QT. I have tried doing this in the following way:
#include <QtGui/QApplication> #include "mainwindow.h" int main(int argc, char *argv[]) { QApplication a(argc, argv); int window_width = QApplication::desktop()->width(); int window_height = QApplication::desktop()->height(); MainWindow w; QPushButton * quit_btn = new QPushButton; quit_btn->setParent(w.centralWidget()); quit_btn->setGeometry(window_width-50,12,32,32); QObject::connect(quit_btn,SIGNAL(clicked()),qApp,SLOT(quit())); w.resize(window_width,window_height); w.show(); return a.exec(); }
Unfortunately when I push the button, the debugger gives an error:
Invalid address specified to RtlFreeHeap( 003E0000, 0028F950 )
Can anybody point me in the right direction?