How to create a Restful web service with input parameters?
Solution 1
You can. Try something like this:
@Path("/todo/{varX}/{varY}")
@Produces({"application/xml", "application/json"})
public Todo whatEverNameYouLike(@PathParam("varX") String varX,
@PathParam("varY") String varY) {
Todo todo = new Todo();
todo.setSummary(varX);
todo.setDescription(varY);
return todo;
}
Then call your service with this URL;
http://localhost:8088/JerseyJAXB/rest/todo/summary/description
Solution 2
If you want query parameters, you use @QueryParam
.
public Todo getXML(@QueryParam("summary") String x,
@QueryParam("description") String y)
But you won't be able to send a PUT from a plain web browser (today). If you type in the URL directly, it will be a GET.
Philosophically, this looks like it should be a POST, though. In REST, you typically either POST to a common resource, /todo
, where that resource creates and returns a new resource, or you PUT to a specifically-identified resource, like /todo/<id>
, for creation and/or update.
Solution 3
Be careful. For this you need @GET (not @PUT).
Solution 4
another way to do is get the UriInfo instead of all the QueryParam
Then you will be able to get the queryParam as per needed in your code
@GET
@Path("/query")
public Response getUsers(@Context UriInfo info) {
String param_1 = info.getQueryParameters().getFirst("param_1");
String param_2 = info.getQueryParameters().getFirst("param_2");
return Response ;
}
SSG
Updated on July 09, 2022Comments
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SSG almost 2 years
I am creating restful web service and i wanted to know how do we create a service with input parameters and also how to invoke it from a web browser.
For example
@Path("/todo") public class TodoResource { // This method is called if XMLis request @PUT @Produces( {MediaType.APPLICATION_XML,MediaType.APPLICATION_JSON}) public Todo getXML() { Todo todo = new Todo(); todo.setSummary("This is my first todo"); todo.setDescription("This is my first todo"); return todo; }
and i can invoke it using http://localhost:8088/JerseyJAXB/rest/todo
and I want to create a method like
@Path("/todo") public class TodoResource { // This method is called if XMLis request @PUT @Produces( {MediaType.APPLICATION_XML,MediaType.APPLICATION_JSON}) public Todo getXML(String x, String y) { Todo todo = new Todo(); todo.setSummary(x); todo.setDescription(y); return todo; }
In case of soap based web services i would invoke it like this
http://localhost:8088/JerseyJAXB/rest/todo?x=abc&y=pqr
but I want to know how to invoke it using rest and also can I pass the parameters as I am doing in the above example when I use rest and jersey.
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Mr. Lance E Sloan about 8 yearsThis answer best addresses the URL parameters mentioned in the original question. Whether parameters or path elements are better for this purpose is another question.