How to create an interface in Swift
Solution 1
Instead of interface swift have Protocols.
A protocol defines a blueprint of methods, properties, and other requirements that suit a particular task or piece of functionality. The protocol can then be adopted by a class, structure, or enumeration to provide an actual implementation of those requirements. Any type that satisfies the requirements of a protocol is said to conform to that protocol.
lets take an exam .
protocol Animal {
func canSwim() -> Bool
}
and we have a class that confirm this protocol name Animal
class Human : Animal {
func canSwim() -> Bool {
return true
}
}
for more go to - https://developer.apple.com/library/content/documentation/Swift/Conceptual/Swift_Programming_Language/Protocols.html
Solution 2
What are you finding is `Protocol'. Interfaces are same as protocol in Swift.
protocol Shape {
func shapeName() -> String
}
class Circle: Shape {
func shapeName() -> String {
return "circle"
}
}
class Triangle: Shape {
func shapeName() -> String {
return "triangle"
}
}
class
and struct
both can implements the protocol
.
Jayprakash Singh
Updated on September 01, 2020Comments
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Jayprakash Singh over 3 years
i want to create functionality like interface in swift, my goal is when i call another class suppose i'm calling API and the response of that class i want to reflect in to my current screen, in android interface is used to achieve but what should i use in swift for that? can anyone help me with example. the code for android is given below...
public class ExecuteServerReq { public GetResponse getResponse = null; public void somemethod() { getResponse.onResponse(Response); } public interface GetResponse { void onResponse(String objects); } } ExecuteServerReq executeServerReq = new ExecuteServerReq(); executeServerReq.getResponse = new ExecuteServerReq.GetResponse() { @Override public void onResponse(String objects) { } }