How to declare an __stdcall function pointer
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As MSDN says, the correct way to write this is
typedef void (__stdcall *MessageHandler)(const Task*);
Author by
Armen Tsirunyan
Updated on June 18, 2022Comments
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Armen Tsirunyan almost 2 years
I tried this
typedef void (* __stdcall MessageHandler)(const Task*);
This compiles but gives me this warning (VS2003):
warning C4229: anachronism used : modifiers on data are ignored
I want to declare a pointer to a function with stdcall calling convention? What am I doing wrong?