How to dismiss own view controller and present another view controller in a button tap?

26,519

Solution 1

you can do using protocol let say for example as bellow:-

In to your B viewController setting Protocol :

@class Bviewcontroller;

@protocol BviewControllerDelegate <NSObject>
- (void)BviewcontrollerDidTapButton:
(Bviewcontroller *)controller;

@end

@interface Bviewcontroller : UIViewcontroller

@property (nonatomic, weak) id <BviewControllerDelegate> delegate;
- (IBAction)ButtonTap:(id)sender;

@end

in .m class

- (IBAction)ButtonTap:(id)sender
{
    [self.delegate BviewcontrollerDidTapButton:self];
}

Now in to you A_viewController .h class:

#import "Bviewcontroller.h"

@interface A_viewController : UIViewcontroller<BviewControllerDelegate>

.m class

- (void)BviewcontrollerDidTapButton:
(Bviewcontroller *)controller
{
    [self dismissViewControllerAnimated:YES completion:^{


      // here you can create a code for presetn C viewcontroller 

    }];
}

IMPORTANT when you preseting Bviewcontroller from A_viewController do not set delegate with object like

-(void)presentNextViewCon
{
                bViewcontroller *gestureViewCon = [[bViewcontroller alloc]init];
        gestureViewCon.delegate = self;

[self presentViewController:gestureViewCon animated:YES completion:nil];

}

UPDATE

Here it is i create a demo that working like:

enter image description here

SAMPLE CODE LINK http://speedy.sh/2acSC/modelDemo.zip

Solution 2

You are taking about a Button lets name it controlButton. Pass that button with B and C with custom init method. That means your UIViewController A is having controllButton reference. Using the method

- (void)addTarget:(id)target action:(SEL)action forControlEvents:(UIControlEvents)controlEvents 

set the trigger block in A and like this

[_controllButton addTarget:self action:@selector(controllButtonTapped:)....];

- (void)controllButtonTapped:(id)sender {

    [self dismissViewControllerAnimated:YES completion:^{

        // present you c here

        [self presentViewController:c animated:YES completion:NULL];
    }];
}

But the best option is to go with “Mediator Design pattern” where a coordinator is coordinating your present and dismiss actions.

Solution 3

It seems that it is not possible to go from B to C without showing A briefly, which looks unprofessional. However, you can put a black subview over top of A until you've animated to C.

In Swift 3:

class A : UIViewController {
    ...
    func showB() {
        // Adding the black view before dismissing B does not work;
        // the view is not displayed.
        let black = UIView()
        black.backgroundColor = UIColor.black
        black.frame = self.view.bounds // assumes A is not zoomed

        let b = B()
        self.present(b, animated:true, completion: {
            self.view.addSubview(black)
        })

        // Note: self.present() will start the animation,
        // then b.imDone will be set.  It is done here for
        // clarity of what happens next, as if it were all
        // one function.
        b.imDone = {
            b.dismiss(animated:false, completion: {
                self.present(C(), animated:true, completion: {
                    black?.removeFromSuperview()
                })
            })
        }
    }
}

class B : UIViewController {
    var imDone : (() -> Void)?
    ...
    func f()
    {
        imDone?()
    }
    ...
}

class C : UIViewController
{
    ...
}

Solution 4

You can not dismiss B and present C simultaneously.

To perform this task you should follow some tasks.

  • On pressing button on 'B' , Dissmiss 'B' without animation and set an global BOOL variable to notify that you want to present 'C'.
  • On -(void)viewDidAppear:(BOOL)animated of 'A'

    if (bool){ [self presentViewController:c animated:YES completion:nil]; }

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user3526002
Author by

user3526002

Updated on September 04, 2020

Comments

  • user3526002
    user3526002 over 3 years

    Let's say I have 3 view controller labeled "A","B" and "C". Right now, "A" is the rootViewController of the window and it presents "B" modally when a button is tapped. In "B", when a button is tapped it is supposed to be dismissed by "A" and then "A" will present C modally immediately.How can one do that? Here's my code in hope of achieving this goal but I was unsuccessful in doing so.

    At "A" viewController, I declared a property to hold a block at the header file to be called when "B" viewController is dismissed by "A".

    @property (nonatomic, copy) void (^presentZapLaunch)(void);
    

    This is "A" viewController present method to present "B"

    -(void)presentNextViewCon
    {
    CYCGestureZapZapViewController *gestureViewCon = [[CYCGestureZapZapViewController alloc]init];
    
    if (!self.presentZapLaunch) {
        __weak CYCZapZapViewController *weakRefCon = self;
    
        self.presentZapLaunch = ^{
            CYCZapZapViewController *preventWeakRefCon = weakRefCon;
    
            CYCZapZapLaunchViewController *zapLaunch = [[CYCZapZapLaunchViewController     alloc]init];
            NSLog(@"Called");
            [preventWeakRefCon presentViewController:zapLaunch animated:YES completion:nil];
    
        };
    }
    
    
    [self presentViewController:gestureViewCon animated:YES completion:nil];
    
    }
    

    This is "B" dismiss method to dismissed by "A" and "A" should present "C" immediately

    -(void)presentNextViewCon
    {
    NSLog(@"Hello");
    [self.presentingViewController dismissViewControllerAnimated:self completion:^{[(CYCZapZapViewController *)self.presentingViewController presentZapLaunch];}];
    
    }
    

    *Note that I'm using "A" view controller as the rootViewController of window, and "A" presents "B" view controller modally. All "A","B" and "C" are view controllers.