How to find element by attribute value in GPath?
Solution 1
Here is the corresponding snippet:
def node = new XmlSlurper().parseText(...)
def foo = node.depthFirst().findAll { it.name() == 'div' && it.@id == 'foo'}
A few other links you may want to read:
Solution 2
The previous poster gave you all that's required: Assuming your document has been slurped into xml
, you want
def foo = xml.path.to.div.find{it.@id == 'foo'}
to find a single result. Or findAll
to find all results.
Solution 3
To mimic the expression //div[@id='foo'] the closest thing you can do with a GPath is:
def xml = new XmlParser().parseText(text)
xml.'**'.div.findAll { it.@id=="foo" }
the '**' is pretty much the same as '//' in your XPath.
xml.'**'.div
will yield all the nodes of type div at any level.
Later filtering with findAll() with the given closure you get a list of nodes as you do in the XPath case
Solution 4
what you need is this:
def root = new XmlSlurper().parseText(<locOfXmlFileYouAreParsing>.toURL().text)
def foundNode = root.'**'.find{ it.@id == "foo" }
its the double * that will let you find it without knowing the path. At least this is how I do it.
yegor256
Lab director at Huawei, co-founder at Zerocracy, blogger at yegor256.com, author of Elegant Objects book; architect of Zold.
Updated on December 11, 2020Comments
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yegor256 over 3 years
What is an alternative to this XPath
//div[@id='foo']
in GPath? In general, where I can find this documentation? -
yegor256 almost 13 yearsIt's Groovy, not GPath. I need a single GPath expression.
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Nicolas Modrzyk almost 13 yearsNot too sure what you mean, since GPath is mostly using groovy syntax with the following extra symbols: ".." that returns the parent "" that returns all the children "*" that act as a depth first loop "@" that is used to access a property the normal node accessor.
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yegor256 almost 13 years
//
in XPath means that I don't know the exact path todiv
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winstaan74 almost 13 yearsok. then the previous poster gave you the solution: - use
xml.depthFirst().find{it.name() == 'div' && id.@id == 'foo}
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raffian over 11 yearsHow do you find the first instance of a node by element name, assuming there's more than one?
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raffian almost 10 years@winstaan74 What's the expression for getting all elements with a specific attribute name?
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AbuNassar almost 8 years
xml.'**'.findAll { it.@attributeName }
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AbuNassar almost 8 years
xml.'**'.find { it.name() == 'elementName' }
And that will be the first one.