How to find the numbers in the thousands, hundreds, tens, and ones place in PYTHON for an input number? For example: 256 has 6 ones, 5 tens, etc

Question

num = int(input("Please give me a number: "))
print(num)
thou = int((num // 1000))
print(thou)
hun = int((num // 100))
print(hun)
ten =int((num // 10))
print(ten)
one = int((num // 1))
print(one)

I tried this but it does not work and I'm stuck.

Solution 1

You might want to try something like following:

def get_pos_nums(num):
    pos_nums = []
    while num != 0:
        pos_nums.append(num % 10)
        num = num // 10
    return pos_nums

And call this method as following.

>>> get_pos_nums(9876)
[6, 7, 8, 9]

The 0th index will contain the units, 1st index will contain tens, 2nd index will contain hundreds and so on...

This function will fail with negative numbers. I leave the handling of negative numbers for you to figure out as an exercise.

Solution 2

Like this?

a = str(input('Please give me a number: '))

for i in a[::-1]:
    print(i)

---

Demo:

Please give me a number: 1324
4
2
3
1

So the first number is ones, next is tens, etc.

Solution 3

You could try splitting the number using this function:

def get_place_values(n):
    return [int(value) * 10**place for place, value in enumerate(str(n)[::-1])]

For example:

get_place_values(342)
>>> [2, 40, 300]

Next, you could write a helper function:

def get_place_val_to_word(n):
    n_str = str(n)
    num_to_word = {
        "0": "ones",
        "1": "tens",
        "2": "hundreds",
        "3": "thousands"
    }
    return f"{n_str[0]} {num_to_word[str(n_str.count('0'))]}"

Then you can combine the two like so:

def print_place_values(n):
    for value in get_place_values(n):
        print(get_place_val_to_word(value))

For example:

num = int(input("Please give me a number: "))
# User enters 342
print_place_values(num)
>>> 2 ones
4 tens
3 hundreds

Comments

[hectorcanto]

A code-styled, function-based program might be better: python def tens_of_number(number: int): return number % 100 / 10 num = 1234 print("tens of ", num, ":", tens_of_number(num))

[Santosh Kumar]

This is a good hack. But interviewers don't want this.