How to get an object's methods?
Solution 1
function getMethods(obj)
{
var res = [];
for(var m in obj) {
if(typeof obj[m] == "function") {
res.push(m)
}
}
return res;
}
Solution 2
Remember that technically javascript objects don't have methods. They have properties, some of which may be function objects. That means that you can enumerate the methods in an object just like you can enumerate the properties. This (or something close to this) should work:
var bar
for (bar in foo)
{
console.log("Foo has property " + bar);
}
There are complications to this because some properties of objects aren't enumerable so you won't be able to find every function on the object.
Solution 3
You can use console.dir(object)
to write that objects properties to the console.
Solution 4
In modern browsers you can use Object.getOwnPropertyNames
to get all properties (both enumerable and non-enumerable) on an object. For instance:
function Person ( age, name ) {
this.age = age;
this.name = name;
}
Person.prototype.greet = function () {
return "My name is " + this.name;
};
Person.prototype.age = function () {
this.age = this.age + 1;
};
// ["constructor", "greet", "age"]
Object.getOwnPropertyNames( Person.prototype );
Note that this only retrieves own-properties, so it will not return properties found elsewhere on the prototype chain. That, however, doesn't appear to be your request so I will assume this approach is sufficient.
If you would only like to see enumerable properties, you can instead use Object.keys
. This would return the same collection, minus the non-enumerable constructor
property.
Solution 5
The methods can be inspected in the prototype chain of the object using the browser's developer tools (F12):
console.log(yourJSObject);
or more directly
console.dir(yourJSObject.__proto__);
thom
Updated on May 30, 2020Comments
-
thom almost 4 years
Is there a method or propertie to get all methods from an object? For example:
function foo() {} foo.prototype.a = function() {} foo.prototype.b = function() {} foo.get_methods(); // returns ['a', 'b'];
UPDATE: Are there any method like that in Jquery?
Thank you.