How to get current time in python and break up into year, month, day, hour, minute?

Question

I would like to get the current time in Python and assign them into variables like year, month, day, hour, minute. How can this be done in Python 2.7?

Solution 1

The datetime module is your friend:

import datetime
now = datetime.datetime.now()
print(now.year, now.month, now.day, now.hour, now.minute, now.second)
# 2015 5 6 8 53 40

You don't need separate variables, the attributes on the returned datetime object have all you need.

Solution 2

Here's a one-liner that comes in just under the 80 char line max.

import time
year, month, day, hour, min = map(int, time.strftime("%Y %m %d %H %M").split())

Solution 3

The datetime answer by tzaman is much cleaner, but you can do it with the original python time module:

import time
strings = time.strftime("%Y,%m,%d,%H,%M,%S")
t = strings.split(',')
numbers = [ int(x) for x in t ]
print numbers

Output:

[2016, 3, 11, 8, 29, 47]

Solution 4

By unpacking timetuple of datetime object, you should get what you want:

from datetime import datetime

n = datetime.now()
t = n.timetuple()
y, m, d, h, min, sec, wd, yd, i = t

Solution 5

Let's see how to get and print day,month,year in python from current time:

import datetime

now = datetime.datetime.now()
year = '{:02d}'.format(now.year)
month = '{:02d}'.format(now.month)
day = '{:02d}'.format(now.day)
hour = '{:02d}'.format(now.hour)
minute = '{:02d}'.format(now.minute)
day_month_year = '{}-{}-{}'.format(year, month, day)

print('day_month_year: ' + day_month_year)

result:

day_month_year: 2019-03-26

View more solutions

Comments

[Sean.H]

just a suplyment: import time \n now=time.localtime() \n print now.tm_year, now.tm_mon, now.tm_mday, now.tm_hour, now.tm_hour, now.tm_min, now.tm_sec, now.tm_wday, now.tm_yday, now.tm_isdst

[Armster]

Heads up: you are shadowing the builtin function "min"