How to get first match with sed?

Question

I am tired of this sed :D So I have a small file:

version = "1.1"
group= "com.centurion.eye"
archivesBaseName = "eye"

impmet {
    version = "4.1614"
    runDir = "eclipse"
}

And here is my sed command:

sed -n -e '/version/ s/.* = *//p' "build.gradle"

And I need to get ONLY version 1.1. So when I execute this command, the output is:

"1.3"
"4.1614"

But desired one is:

"1.3"

How can I achieve that? Thanks!

Solution 1

pipe your commands output to head -1 to get only the first entry.

sed -n -e '/version/ s/.* = *//p' "build.gradle" | head -1

Sample Run

[ /c]$ cat build.gradle
version = "1.1"
group= "com.centurion.eye"
archivesBaseName = "eye"

impmet {
    version = "4.1614"
        runDir = "eclipse"
        }
[ /c]$ sed -n -e '/version/ s/.* = *//p' build.gradle | head -1
"1.1"

Solution 2

Quit after matching the first one.

sed -n -e '/version/ {s/.* = *//p;q}' build.gradle

Solution 3

With GNU sed, you can also use 0 in the address range to apply substitution only on the first match:

sed -n -e '0,/version/s/.* = *//p' build.gradle