use SED recursively in linux?

Question

I want to implement the following command recursively

sed -i 's/href=\"1\//href=\"\/1\//g' ./*

so that it replaces all href="1 with href="/1 in all sub-directories. Is there a flag I can add to this command to achieve the results I want?

Solution 1

find . -type f -print0 | xargs -0 sed -i 's/href=\"1\//href=\"\/1\//g'

Solution 2

Per https://stackoverflow.com/a/5130044/833771, if the target directory is a Git or SVN root, you should use: find . -not \( -name .svn -prune -o -name .git -prune \) -type f -print0 | xargs -0 sed -i 's/href=\"1\//href=\"\/1\//g'

Comments

[James]

It should be -0 - it matches up with -print0 in the find - edited the post.

[John]

I find that find . -type f | xargs sed -i 's/href=\"1\//href=\"\/1\//g' can produce the same results. Will there be pitfalls to this approach?