how to get video from ip camera using emgucv

Question

Summary:

I'm trying to get video from IP camera in emgu, I could display video in the browser from an ip like "http://169.254.255.253".

Question:

How could I display this from emgu?

Solution 1

Capture _Capture = new Emgu.CV.CvInvoke.cvCreateFileCapture("http://username:pass@cam_address/axis-cgi/mjpg/video.cgi?resolution=640x480&req_fps=30&.mjpg");

I didn't test but may be this code snippet or approach can help you. For OpenCV example you can examine this page: OpenCV with Network Cameras

And you can examine this method's wiki page: http://www.emgu.com/wiki/files/2.3.0/document/html/a26a5e9d-53d7-633a-5d50-508aa22dd1fd.htm

Solution 2

If you are using Emgu 3.1 then try this:

Capture cameraCapture
cameraCapture = new Capture("http://user:passwd@http://169.254.255.253");
Mat frame = cameraCapture.QueryFrame();
imageBox1.Image = frame;

here is the Capture Class Reference:

http://www.emgu.com/wiki/files/3.1.0/document/html/5edc4ff8-cec3-c5ee-8e62-629cf4c7940a.htm

Hope it helps.

Comments

[mostafa8026]

thank you, but your code doesn't work properly, cvCreateFileCapture return IntPtr. so i use that like : IntPtr i = Emgu.CV.CvInvoke.cvCreateFileCapture("192.168.1.253/…); but I don't know how to get video from url?!!

[Kerberos]

OK, Normally capture object can get int param. Int param means is index of camera on your system. For example if you use like this "Capture _Capture = New Capture(0);" you define your system camera which index number is zero. See this page for more detail: emgu.com/wiki/files/2.3.0/document/html/…