How to handle command-line arguments in PowerShell

808,266

You are reinventing the wheel. Normal PowerShell scripts have parameters starting with -, like script.ps1 -server http://devserver

Then you handle them in a param section (note that this must begin at the first non-commented line in your script).

You can also assign default values to your params, read them from console if not available or stop script execution:

 param (
    [string]$server = "http://defaultserver",
    [Parameter(Mandatory=$true)][string]$username,
    [string]$password = $( Read-Host "Input password, please" )
 )

Inside the script you can simply

write-output $server

since all parameters become variables available in script scope.

In this example, the $server gets a default value if the script is called without it, script stops if you omit the -username parameter and asks for terminal input if -password is omitted.

Update: You might also want to pass a "flag" (a boolean true/false parameter) to a PowerShell script. For instance, your script may accept a "force" where the script runs in a more careful mode when force is not used.

The keyword for that is [switch] parameter type:

 param (
    [string]$server = "http://defaultserver",
    [string]$password = $( Read-Host "Input password, please" ),
    [switch]$force = $false
 )

Inside the script then you would work with it like this:

if ($force) {
  //deletes a file or does something "bad"
}

Now, when calling the script you'd set the switch/flag parameter like this:

.\yourscript.ps1 -server "http://otherserver" -force

If you explicitly want to state that the flag is not set, there is a special syntax for that

.\yourscript.ps1 -server "http://otherserver" -force:$false

Links to relevant Microsoft documentation (for PowerShell 5.0; tho versions 3.0 and 4.0 are also available at the links):

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Aaron Wurthmann
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Aaron Wurthmann

Updated on July 08, 2022

Comments

  • Aaron Wurthmann
    Aaron Wurthmann almost 2 years

    What is the "best" way to handle command-line arguments?

    It seems like there are several answers on what the "best" way is and as a result I am stuck on how to handle something as simple as:

    script.ps1 /n name /d domain
    

    AND

    script.ps1 /d domain /n name.
    

    Is there a plugin that can handle this better? I know I am reinventing the wheel here.

    Obviously what I have already isn't pretty and surely isn't the "best", but it works.. and it is UGLY.

    for ( $i = 0; $i -lt $args.count; $i++ ) {
        if ($args[ $i ] -eq "/n"){ $strName=$args[ $i+1 ]}
        if ($args[ $i ] -eq "-n"){ $strName=$args[ $i+1 ]}
        if ($args[ $i ] -eq "/d"){ $strDomain=$args[ $i+1 ]}
        if ($args[ $i ] -eq "-d"){ $strDomain=$args[ $i+1 ]}
    }
    Write-Host $strName
    Write-Host $strDomain
    
  • Keith Hill
    Keith Hill over 14 years
    Indeed one of PowerShell's big advantages is that it provides a standard parameter parsing infrastucture that is easy to use.
  • v.karbovnichy
    v.karbovnichy about 10 years
    @naivists, from PowerShell 2.0 instead of [string]$username = $(throw "-username is required.") there is syntax for mandatory parameters: [Parameter(Mandatory=$true)][string]$username. Here is more info about difference between these techniques: blogs.technet.com/b/heyscriptingguy/archive/2011/05/22/…
  • sheamus
    sheamus over 9 years
    Be wary of the bug when an arg is not supplied; powershell will just grab any extra text from the command line: .\yourscript.ps1 -server "serv" -password "mypass" typo This will magically assign 'typo' to $username.
  • kuga
    kuga over 7 years
    This is great! Could you make this a documentation? One question though: How to handle parameters with no -option tag?
  • Logan
    Logan over 7 years
    Using a param block seems to have other unintended consequences though: stackoverflow.com/questions/40940819/…
  • Fernando Madruga
    Fernando Madruga over 6 years
    @sheamus: that is not a bug! Powershell will process and assign the arguments in the order they're given, unless overridden by using the proper parameter name, e.g., if your param block lists: $user $pass $server, and you execute yourscript.ps1 a b c, a will be set into $user, b into $pass and c into $server, UNLESS you specifically assign them! So, if you say: yourscript.ps1 -pass a b c, $pass will be set to a, and the remaining (unnamed) parameters will be used to fill in the missing ones, in the order listed in the parameter block, so $user = b, $server = c.
  • jpmc26
    jpmc26 about 6 years
    The better way to do username and password is to use the Credential type, which will take care of hiding the password during typing and storing it as a SecureString. (I'm not totally sold on the value of SecureString, but at least it lowers the risk of it getting accidentally printed in the output.)
  • Scrontch
    Scrontch over 4 years
    Great. But how to check if there are parameters given at all? In order to print a usage message for example.
  • naivists
    naivists over 4 years
    @Scrontch, see this answer to a similar question: stackoverflow.com/a/48643616/239599
  • basickarl
    basickarl over 4 years
    Wow, you couldn't of just made an example file?
  • Justin
    Justin over 4 years
    @sheamus one way to avoid the "typo" scenario is to explicitly deny positional binding, this can be done per parameter or globally. just add [CmdletBinding(PositionalBinding=$false)] to the top of your cmdlet.
  • Timo
    Timo over 3 years
    Here is a nice example for positional arguments which goes more along the linux path.
  • yoyo
    yoyo over 3 years
    @Timo awesome link, thanks, just what I needed! [Parameter(ValueFromRemainingArguments=$True, Position=0)] is the magic that prevents optional named parameters from consuming positional parameters.
  • CODE-REaD
    CODE-REaD about 2 years
    Being a novice PowerShell programmer, I struggled for a good while with the error The term 'param' is not recognized as the name of a cmdlet, function, script file. The solution turned out to be simple: I can use this function only as the first non-commented line of code in my script!