How to make POST NSURLRequest with 2 parameters?
19,997
Solution 1
It will probably be easier to do if you use AFNetworking. If you have some desire to do it yourself, you can use NSURLSession
, but you have to write more code.
If you use AFNetworking, it takes care of all of this gory details of serializing the request, differentiating between success and errors, etc.:
NSDictionary *params = @{@"firstname": @"John", @"lastname": @"Doe"}; AFHTTPSessionManager *manager = [AFHTTPSessionManager manager]; [manager POST:urlString parameters:params success:^(NSURLSessionDataTask *task, id responseObject) { NSLog(@"responseObject = %@", responseObject); } failure:^(NSURLSessionDataTask *task, NSError *error) { NSLog(@"error = %@", error); }];
This assumes that the response from the server is JSON. If not (e.g. if plain text or HTML), you might precede the
POST
with:manager.responseSerializer = [AFHTTPResponseSerializer serializer];
If doing it yourself with
NSURLSession
, you might construct the request like so:NSDictionary *params = @{@"firstname": @"John", @"lastname": @"Doe"}; NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url]; [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"]; [request setHTTPMethod:@"POST"]; [request setHTTPBody:[self httpBodyForParameters:params]];
You now can initiate the request with
NSURLSession
. For example, you might do:NSURLSessionTask *task = [[NSURLSession sharedSession] dataTaskWithRequest:request completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) { if (error) { NSLog(@"dataTaskWithRequest error: %@", error); } if ([response isKindOfClass:[NSHTTPURLResponse class]]) { NSInteger statusCode = [(NSHTTPURLResponse *)response statusCode]; if (statusCode != 200) { NSLog(@"Expected responseCode == 200; received %ld", (long)statusCode); } } // If response was JSON (hopefully you designed web service that returns JSON!), // you might parse it like so: // // NSError *parseError; // id responseObject = [NSJSONSerialization JSONObjectWithData:data options:0 error:&parseError]; // if (!responseObject) { // NSLog(@"JSON parse error: %@", parseError); // } else { // NSLog(@"responseObject = %@", responseObject); // } // if response was text/html, you might convert it to a string like so: // // NSString *responseString = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding]; // NSLog(@"responseString = %@", responseString); }]; [task resume];
Where
/** Build the body of a `application/x-www-form-urlencoded` request from a dictionary of keys and string values @param parameters The dictionary of parameters. @return The `application/x-www-form-urlencoded` body of the form `key1=value1&key2=value2` */ - (NSData *)httpBodyForParameters:(NSDictionary *)parameters { NSMutableArray *parameterArray = [NSMutableArray array]; [parameters enumerateKeysAndObjectsUsingBlock:^(NSString *key, NSString *obj, BOOL *stop) { NSString *param = [NSString stringWithFormat:@"%@=%@", [self percentEscapeString:key], [self percentEscapeString:obj]]; [parameterArray addObject:param]; }]; NSString *string = [parameterArray componentsJoinedByString:@"&"]; return [string dataUsingEncoding:NSUTF8StringEncoding]; }
and
/** Percent escapes values to be added to a URL query as specified in RFC 3986. See http://www.ietf.org/rfc/rfc3986.txt @param string The string to be escaped. @return The escaped string. */ - (NSString *)percentEscapeString:(NSString *)string { NSCharacterSet *allowed = [NSCharacterSet characterSetWithCharactersInString:@"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789-._~"]; return [string stringByAddingPercentEncodingWithAllowedCharacters:allowed]; }
Solution 2
NSDictionary *params = @{@"firstname": @"John", @"lastname": @"Doe"};
NSMutableString *str = [NSMutableString stringWithString:@"http://yoururl.com/postname?"];
NSArray *keys = [params allKeys];
NSInteger counter = 0;
for (NSString *key in keys) {
[str appendString:key];
[str appendString:@"="];
[str appendString:params[key]];
if (++counter < keys.count) { // more params to come...
[str appendString:@"&"];
}
}
NSURL *url = [NSURL URLWithString:str];
// should give you: http://yoururl.com/postname?firstname=John&lastname=Doe
// not tested, though
Comments
-
l.vasilev almost 2 years
I want to add 2 parameters to
NSURLRequest
. Is there a way or should I use AFnetworking? -
CouchDeveloper over 9 years
URLWithString
requires a properly encoded URL. Your approach does not encode the URL components at all. So, it will fail eventually. -
l.vasilev over 9 yearsyes i am receiving JSON .this is great and complete answer.THAKS man! :) Can i ask you just one thing for AFNetworking. this is my code :[manager POST:@"tourneys/portal.php" parameters:@{ @"cmd":@"get_games", @"uid_first":@"1" } success:^(NSURLSessionDataTask task, id responseObject) { NSDictionary response = (NSDictionary* )responseObject; I am receiving json from my server. Is this cast to NSDictionary valid .I saw it's working but i can't figure it out why.I am not using explicit any serialiser. Thanks in advance.
-
Rob over 9 yearsSince you haven't specified a
responseSerializer
, that means you're using the defaultAFJSONResponseSerializer
. So, it's doing the JSON conversion for you. -
AppsolutEinfach almost 8 yearsFor iOS 9 replace
CFURLCreateStringByAddingPercentEscapes()
bystringByAddingPercentEncodingWithAllowedCharacters:[NSCharacterSet URLQueryAllowedCharacterSet]
inpercentEscapeString:
. -
Rob almost 8 years@AppsolutEinfach - No, because that character set will let
&
and+
pass unescaped (because they're allowed in query URL; but if these delimiters occur within value within query, you have to escape them). See part 2 of stackoverflow.com/a/35912606/1271826 if you want to see how you have to modifyURLQueryAllowedCharacterSet
properly. -
AppsolutEinfach almost 8 years@Rob - You're totally right. Thanks for your correction.
-
Nat over 5 yearsI would argue that attaching libraries is the best way of doing everything. AFNetworking is not required at this point. No need to attach extra dependency.
-
Rob over 5 yearsTo each his own. That’s why I outlined both approaches above.
-
Doon over 4 yearsIt won't "fail eventually". It will fail if some special char is in the parameter