How to pass output of grep to sed?
18,857
Solution 1
If the intention is to print the lines that grep
returns, generating a sed
script might be the way to go:
grep -E -o '[0-9]+' error | sed 's/$/p/' | sed -f - error
Solution 2
You are probably looking for xargs
, particularly the -I
option:
themel@eristoteles:~$ xargs -I FOO echo once FOO, twice FOO
hi
once hi, twice hi
there
once there, twice there
Your example:
themel@eristoteles:~$ cat error
error in line 123
error in line 234
errors in line 345 and 346
themel@eristoteles:~$ grep -o '[0-9]*' < error | xargs -I OutPutFromGrep echo sed -n 'OutPutFromGrep,OutPutFromGrepp'
sed -n 123,123p
sed -n 234,234p
sed -n 345,345p
sed -n 346,346p
For real-world use, you'll probably want to pass sed
an input file and remove the echo
.
(Fixed your UUOC, by the way. )
Author by
batman
Updated on July 20, 2022Comments
-
batman almost 2 years
I have a command like this :
cat error | grep -o [0-9]
which is printing only numbers like
2
,30
and so on. Now I wish to pass this number tosed
.Something like :
cat error | grep -o [0-9] | sed -n '$OutPutFromGrep,$OutPutFromGrepp'
Is it possible to do so?
I'm new to shell scripting. Thanks in advance
-
batman over 11 years+1 Nice.
cat error | grep -o [0-9]+
After this I have the data, now how I can pass it tosed
?