How to select element using XPATH syntax on Selenium for Python?
150,165
HTML
<div id='a'>
<div>
<a class='click'>abc</a>
</div>
</div>
You could use the XPATH as :
//div[@id='a']//a[@class='click']
output
<a class="click">abc</a>
That said your Python code should be as :
driver.find_element_by_xpath("//div[@id='a']//a[@class='click']")
Author by
user2534633
Updated on February 12, 2021Comments
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user2534633 over 3 years
consider following HTML:
<div id='a'> <div> <a class='click'>abc</a> </div> </div>
I want to click abc, but the wrapper div could change, so
driver.get_element_by_xpath("//div[@id='a']/div/a[@class='click']")
is not what I want
i tried:
driver.get_element_by_xpath("//div[@id='a']").get_element_by_xpath(.//a[@class='click']")
but this would not work with deeper nesting
any ideas?