how to send url parameter in POST request without form

django url httpwebrequest url-parameters

21,720

Solution 1

You can still use a html form but "hide" it from the user:

<!DOCTYPE html>
<html>
    <body>
        <form id="myform" method="post" action="/">
            {% csrf_token %}
            <input type="hidden" name="flag" value="2" />
            <a href="#" onclick="document.forms[0].submit();return false;">Let's go!</a>
        </form>
    </body>
</html>

And the view:

def index(request):
    if request.method == 'POST':
        try:
            flag = request.POST['flag']
            # TODO use flag
        except KeyError:
            print 'Where is my flag?'

    return render_to_response('index.html', {},
        context_instance=RequestContext(request))

Solution 2

You can use AJAX to get rid of forms entirely.

Just add this to your JavaScript:

function postTo(url, query) {
    var request = (XMLHttpRequest?new XMLHttpRequest():new ActiveXObject());
    request.open('POST', url, true);
    request.send(query);
}

Then call with something like this:

postTo('/admin/usermanagement/','flag=2');

Note that this will NOT reload the page. If you want to reload the page, use Borges' answer.

21,720

Author by

Nazneen

Im an IT professional working as Software Engineer

Updated on July 22, 2020

Comments

Nazneen almost 4 years
I have to pass a parameter in url. I can't send it in as usual GET request the variable and value is shown in the address bar with the request. So, the end user can change the value for this variable value and send request which will be processed.
```
href="url=/admin/usermanagement/?flag=2
```
I want to send this hiding flag=2

now this goes as a GET request and it is seen in the address bar. Please give your suggestion if you have any idea on changing this to POST to hide and send the value.