How to sort list inside dict in Python?
13,845
Solution 1
You aren't actually calling the sort
method. Just specifying sort
will return a reference to the sort
method, which isn't even assigned anywhere in your case. In order to actually call it, you should add parenthesis:
for x in ab:
ab[x].sort()
# Here ---^
Solution 2
Not sure if you have a typo in your snippets, but here's one way to sort the values of a dictionary, where the values are lists:
>>> d1 = {"B" : ["x", "z", "k"], "A" : ["a", "c", "b"]}
>>> d2 = {x:sorted(d1[x]) for x in d1.keys()}
>>> d2
{'A': ['a', 'b', 'c'], 'B': ['k', 'x', 'z']}
Author by
Django Learner
Updated on June 20, 2022Comments
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Django Learner almost 2 years
I am trying to sort list inside of dict alphabetically but not able to do it. My list is
{"B" : ["x", "z", "k"], "A" : ["a", "c", "b"]}
What I want to do is,
{"A" : ["k", "x", "z"], "B" : ["a", "b", "c"]}
my codes are
a = {"B" : ["x", "z", "k"], "A" : ["a", "c", "b"]} b = dict() for key, value in a.items(): b[str(key).replace('"','')] = value ab = OrderedDict(sorted(b.items(), key=lambda t: t[0])) for x in ab: ab[x].sort return HttpResponse(json.dumps(ab), content_type="application/json")
the output I am getting is
{ "A" : ["a", "c", "b"], "B" : ["x", "z", "k"]}
can anyone tell me where is my mistake? I am printing out in django template json output.