When I tried to sort a list, I got an error 'dict' object has no attribute

Question

My code which created the list is:

choices = []
for bet in Bet.objects.all():
    #...
    #Here is code that skip loop if bet.choice exist in choices[]
    #...
    temp = {
        'choice':bet.choice,
        'amount':bet.sum,
        'count':bets.filter(choice=bet.choice).count()}
    choices.append(temp)

choices.sort(key=attrgetter('choice'), reverse=True)
choices.sort(key=attrgetter('amount'), reverse=True)
choices.sort(key=attrgetter('count'), reverse=True)

I have to sort by list because model orderby() cant sort by count(),can it?

Solution

Your dictionaries have no choice, amount or count attributes. Those are keys, so you need to use an itemgetter() object instead.

from operator import itemgetter

choices.sort(key=itemgetter('choice'), reverse=True)
choices.sort(key=itemgetter('amount'), reverse=True)
choices.sort(key=itemhetter('count'), reverse=True)

If you want to sort by multiple criteria, just sort once, with the criteria named in order:

choices.sort(key=itemgetter('count', 'amount', 'choice'), reverse=True)

You probably want to have the database do the sorting, however.

Comments

[Zero0Ho]

Oh! It's work now. and I have more question I try this before choices = sorted(choices.items(), key=itemgetter(1)) but it didn't work

[Martijn Pieters]

@ZeroOHo: that's because choices is a list of dictionaries. Lists don't have a .items() method.