How to structure javascript callback so that function scope is maintained properly

38,729

Solution 1

With the code you have provided test will still be in scope inside the callback. xhr will not be, other than xhr.responseText being passed in as data.

Updated from comment:

Assuming your code looks something like this:

for (var test in testers)
  getFileContents("hello"+test+".js", function(data) {
    alert(test);
  });
}

As this script runs, test will be assigned the values of the keys in testers - getFileContents is called each time, which starts a request in the background. As the request finishes, it calls the callback. test is going to contain the FINAL VALUE from the loop, as that loop has already finished executing.

There is a technique you can use called a closure that will fix this sort of problem. You can create a function that returns your callback function, creating a new scope you can hold onto your variables with:

for (var test in testers) {
  getFileContents("hello"+test+".js", 
    (function(test) { // lets create a function who has a single argument "test"
      // inside this function test will refer to the functions argument
      return function(data) {
        // test still refers to the closure functions argument
        alert(test);
      };
    })(test) // immediately call the closure with the current value of test
  );
}

This will basically create a new scope (along with our new function) that will "hold on" to the value of test.

Another way of writing the same sort of thing:

for (var test in testers) {
  (function(test) { // lets create a function who has a single argument "test"
    // inside this function test will refer to the functions argument
    // not the var test from the loop above
    getFileContents("hello"+test+".js", function(data) {
        // test still refers to the closure functions argument
        alert(test);
    });
  })(test); // immediately call the closure with the value of `test` from `testers`
}

Solution 2

JavaScript uses lexical scoping, which basically means that your second code example will work just like how you intend it to work.

Consider the following example, borrowed from David Flanagan's Definitive Guide1:

var x = "global";

function f() {
  var x = "local";
  function g() { alert(x); }
  g();
}

f();  // Calling this function displays "local"

Also keep in mind that unlike C, C++ and Java, JavaScript does not have block-level scope.

In addition, you may also be interested in checking out the following article, which I highly recommend:


1 David Flanagan: JavaScript - The Definitive Guide, Fourth Edition, Page 48.

Solution 3

In this scenario, test will be resolved as you'd expect it, but the value of this might be different. Normally, to preserve the scope, you would make it a parameter to the asynchronous function like so:

function getFileContents(filePath, callbackFn, scope) {  
    var xhr = new XMLHttpRequest();
    xhr.onreadystatechange = function() {
        if (xhr.readyState == 4) {
            callbackFn.call(scope, xhr.responseText);
        }
    }
    xhr.open("GET", chrome.extension.getURL(filePath), true);
    xhr.send();
}


//then to call it:
var test = "lol";

getFileContents("hello.js", function(data) {
    alert(test);
}, this);
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Chetan
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Chetan

Generalist software engineer with 10 years of experience shipping products featured by Apple and Google, ranging from full-stack mobile and web development, game development, UI / UX design, and AI / machine learning.

Updated on December 26, 2020

Comments

  • Chetan
    Chetan over 3 years

    I'm using XMLHttpRequest, and I want to access a local variable in the success callback function.

    Here is the code:

    function getFileContents(filePath, callbackFn) {  
        var xhr = new XMLHttpRequest();
        xhr.onreadystatechange = function() {
            if (xhr.readyState == 4) {
                callbackFn(xhr.responseText);
            }
        }
        xhr.open("GET", chrome.extension.getURL(filePath), true);
        xhr.send();
    }
    

    And I want to call it like this:

    var test = "lol";
    
    getFileContents("hello.js", function(data) {
        alert(test);
    });
    

    Here, test would be out of the scope of the callback function, since only the enclosing function's variables are accessible inside the callback function. What is the best way to pass test to the callback function so the alert(test); will display test correctly?

    Edit:

    Now, if I have the following code calling the function defined above:

    for (var test in testers) {
        getFileContents("hello.js", function(data) {
            alert(test);
        });
    }
    

    The alert(test); code only prints the last value of test from the for loop. How do I make it so that it prints the value of test during the time at which the function getFileContents was called? (I would like to do this without changing getFileContents because it's a very general helper function and I don't want to make it specific by passing a specific variable like test to it.