How to suspend a java thread for a small period of time, like 100 nanoseconds?

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Solution 1

The granularity of sleeps is generally bound by the thread scheduler's interrupt period. In Linux, this interrupt period is generally 1ms in recent kernels. In Windows, the scheduler's interrupt period is normally around 10 or 15 milliseconds

If I have to halt threads for periods less than this, I normally use a busy wait

EDIT: I suspect you'll get best results on jrockit + solaris. The numbers on a windows box are terrible.

@Test
public void testWait(){
    final long INTERVAL = 100;
    long start = System.nanoTime();
    long end=0;
    do{
        end = System.nanoTime();
    }while(start + INTERVAL >= end);
    System.out.println(end - start);
}

Solution 2

For simulation, I would not attempt to simulate in real-time as this doesn't give you reproducible results. i.e. you can't test your simulation.

Instead, I would use a data-driven, simulated clock, and run everything as fast as possible. This gives you reproducible results and allows you to simulate faster than real-time (e.g. 2x to 100x faster)


Suspecting a thread takes around 10 microseconds. There is no point trying to suspend a thread for less time than this.

To busy wait for a short period of time, you can try.

long start = System.nanoTime();
while(start + delay >= System.nanoTime());

Note: as @EugeneBeresovsky comments, after your machine has been running for 292 years this could overflow so you might choose to write this as

while(System.nanoTime() - start < delay);

This will fine for delays of less than 292 years instead. You can use System.currentTimeMillis() for much longer delays.

However, even this is not reliable as System.nanoTime() can take up to 300 ns on Centos 5.x so calling it twice is going to take much longer than 100 ns. Also many OS only have a resolution of 1000 ns (1 micro-second) so this loop will wait up to 1 micro-second regardless of the delay you are looking for.

Instead what you can do is to busy wait in a short loop which is not optimised way.

For a delay of 100 ns, I suspect it would be better to busy wait on whatever you are waiting for instead of creating a separate busy loop.

Solution 3

public static void busySleep(long nanos)
{
  long elapsed;
  final long startTime = System.nanoTime();
  do {
    elapsed = System.nanoTime() - startTime;
  } while (elapsed < nanos);
}

Solution 4

Do a busy wait , ( ie have a while loop cycle through so many numbers doing nothing ). A the start of your program you can time the amount of time it took it execute this busy wait and increase or decrease it to get to 5 nano seconds

I have found object.wait gets hairy with this frequency also make note that a busy wait solution would most likely be machine dependent Hence why you should have a calibration step at the start of your program

Solution 5

One more problem with Thread.sleep() is that it is not guaranteed to wakeup after the specified time. A sleeping thread is guarenteed to sleep for the specified nano/micro seconds but not guarenteed to wakeup immediately after that. Since you are talking interms of nanoseconds, you might want to try Object.wait(long, int).

I ve been quite consistent with the order of 10s of nanoseconds with the above method.

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JackWM
Author by

JackWM

Interests: Automata Theory, Parallelism

Updated on July 23, 2022

Comments

  • JackWM
    JackWM almost 2 years

    I know Thread.sleep() can make a java thread suspend for a while, like certain milliseconds and certain nanoseconds. But the problem is the invocation of this function also causes overhead.

    For example, if I want a thread to suspend for 100 nanoseconds, and I call Thread.sleep(0, 100). The whole cost for this process is invocation_cost + 100 nanosceonds, which may be much larger the what I want. How could I avoid this problem, and achieve my purpose?

    The reason I need this is that I want to do simulation offline. I profiled the execution time of a task; Now I want to simulate this execution time by suspending a thread in the same time period.

    Thanks!