How to use Python to convert an octal to a decimal

Question

I had this little homework assignment and I needed to convert decimal to octal and then octal to decimal. I did the first part and could not figure out the second to save my life. The first part went like this:

decimal = int(input("Enter a decimal integer greater than 0: "))

print("Quotient Remainder Octal")
bstring = " "
while decimal > 0:
    remainder = decimal % 8
    decimal = decimal // 8
    bstring = str(remainder) + bstring
    print ("%5d%8d%12s" % (decimal, remainder, bstring))
print("The octal representation is", bstring)

I read how to convert it here: Octal to Decimal, but I have no clue how to turn it into code.

Solution

From decimal to octal:

oct(42) # '052'

Octal to decimal

int('052', 8) # 42

If you want to return octal as a string then you might want to wrap it in str.

Comments

[Jacob]

An explanation along with the answer would be useful.

[Admin]

take into account ))

[joce]

Adding some comments as to why this answers the original poster's question would be welcome.

[Peter Mortensen]

It is identical to your previous answer.

[Peter Mortensen]

An explanation would be in order.