In gdb, I can call some class functions, but others "cannot be resolved". Why?
Solution 1
gdb
is not a compiler, it will not do the (not-so-)nice user-defined type conversions for you. If you wish to call a function that wants a string
, you need to give it a string
, not a const char*
.
Unfortunately, gdb
cannot construct an std::string
for you on the command line, again because it is not a compiler and object creation is not a simple function call.
So you will have to add a little helper function to your program, that would take a const char*
and return an std::string&
. Note the reference here. It cannot return by value, because then gdb
will not be able to pass the result by const reference (it's not a compiler!) You can choose to return a reference to a static object, or to an object allocated on the heap. In the latter case it will leak memory, but this is not a big deal since the function is meant to be called only from the debugger anyway.
std::string& SSS (const char* s)
{
return *(new std::string(s));
}
Then in gdb
gdb> p (paramNode_.px)->Get(SSS("domain"))
should work.
Solution 2
In such a situation I just had success after giving the command
set overload-resolution off
Solution 3
A couple additions to the previous answer --
gdb will probably eventually learn how to do conversions like this. It can't now; but there is active work on improving support for C++ expression parsing.
gdb doesn't understand default arguments, either. This is partly a bug in gdb; but also partly a bug in g++, which doesn't emit them into the DWARF. I think DWARF doesn't even define a way to emit non-trivial default arguments.
Solution 4
n.m.'s answer is great, but to avoid having to edit your code and recompile take a look at the solution given in Creating C++ string in GDB.
In that solution they demonstrate allocating space for a std::string
on the heap and then initializing a std::string
to pass into the function
they'd like to call from gdb
.
Sebastian
Updated on November 11, 2020Comments
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Sebastian over 3 years
I have not worked on shared pointers yet .. I just know the concept. I'm trying to debug functions in the following c++ class, which stores data of an XML file (read-in via the xerces library).
// header file class ParamNode; typedef boost::shared_ptr<ParamNode> PtrParamNode; class ParamNode : public boost::enable_shared_from_this<ParamNode> { public: ... typedef enum { DEFAULT, EX, PASS, INSERT, APPEND } ActionType; bool hasChildren() const; PtrParamNode GetChildren(); PtrParamNode Get(const std::string& name, ActionType = DEFAULT ); protected: .... ActionType defaultAction_; }
Now if I'm debugging a piece of code in which I have an instance of the pointer to the class
ParamNode
, and it's calledparamNode_
PtrParamNode paramNode_; // read xml file with xerces paramNode_ = xerces->CreateParamNodeInstance(); // now, the xml data is stored in paramNode_. std::string probGeo; // this works in the code, but not in (gdb)!! paramNode_->Get("domain")->GetValue("gt",probGeo); cout << probGeo << endl; // <-- breakpoint HERE
Using
gdb
I'm inspecting theparamNode_
object:(gdb) p paramNode_ $29 = {px = 0x295df70, pn = {pi_ = 0x2957ac0}} (gdb) p *paramNode_.px $30 = { <boost::enable_shared_from_this<mainclass::ParamNode>> = {weak_this_ = {px = 0x295df70, pn = {pi_ = 0x2957ac0}}}, _vptr.ParamNode = 0x20d5ad0 <vtable for mainclass::ParamNode+16>, ... name_= {...}, children_ = {size_ = 6, capacity_ = 8, data_ = 0x2969798}, defaultAction_ = mainclass::ParamNode::EX, }
and print its members:
(gdb) ptype *paramNode_.px type = class mainclass::ParamNode : public boost::enable_shared_from_this<mainclass::ParamNode> { protected: ... mainclass::ParamNode::ActionType defaultAction_; public: bool HasChildren(void) const; mainclass::PtrParamNode GetChildren(void); mainclass::PtrParamNode Get(const std::string &, mainclass::ParamNode::ActionType);
However, I can only call the functions
HasChildren
orGetChildren
, whereas callingGet
fromgdb
results in an error:(gdb) p (paramNode_.px)->HasChildren() $7 = true (gdb) p (paramNode_.px)->GetChildren() $8 = (mainclass::ParamNodeList &) @0x295dfb8: { size_ = 6, capacity_ = 8, data_ = 0x29697a8 } (gdb) p (paramNode_.px)->Get("domain") Cannot resolve method mainclass::ParamNode::Get to any overloaded instance (gdb) set overload-resolution off (gdb) p (paramNode_.px)->Get("domain") One of the arguments you tried to pass to Get could not be converted to what the function wants. (gdb) p (paramNode_.px)->Get("domain", (paramNode_.px).defaultAction_) One of the arguments you tried to pass to Get could not be converted to what the function wants.
In the code, executing the
Get("domain")
function works just fine. Why is that? I'm thankful if you include explanations in your answer, due to my limited knowledge of shared pointers. -
Sebastian almost 11 yearsyes, this looks good sir. I need to supply all arguments though (the
DEFAULT
second parameter needs to be supplied as well).(gdb) p (paramNode_.px)->Get(SSS("domain")) Too few arguments in function call.
. However, this works:(gdb) p (paramNode_.px)->Get(SSS("domain"), (paramNode_.px).defaultAction_).px $28 = (mainclass::ParamNode *) 0x2969710
. Thanks for the detailed comments! -
Sebastian almost 11 yearsthanks for this addition. Are you aware of any debuggers which can do this already?
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mallwright over 6 yearsIt would be great if this answer could be expanded a bit further. How does setting this parameter solve the problem?
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ealfonso over 5 yearsin 2018 it seems that it still doesn't know how to do it. at least in the version I am using: 7.9-gg19
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John H. over 5 yearsSee also stackoverflow.com/questions/42462860/… :-)
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Lekensteyn almost 5 years
set overload-resolution off
"Disable overload resolution for C++ expression evaluation. For overloaded functions that are not class member functions, GDB chooses the first function of the specified name that it finds in the symbol table, whether or not its arguments are of the correct type. For overloaded functions that are class member functions, GDB searches for a function whose signature exactly matches the argument types." sourceware.org/gdb/current/onlinedocs/gdb/… -
JohnK over 4 yearsWait, just want to get this straight: is gdb not a compiler?
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user202729 over 2 yearsActually it's possible Creating C++ string in GDB - Stack Overflow