Inside a bash script, how to get PID from a program executed when using the eval command?
Your ampersand is backgrounding the eval
line, causing the (top-level) shell to fork a child, the child shell to eval
the string and in turn run your java program as a grandchild of the top-level shell. So, $!
reports the pid of the child shell, which is the most recently backgrounded command.
Instead move the backgrounding inside your eval:
eval "(java ...) &"
pid=$!
As long as the parenthetical doesn't get complicated enough to become a subshell, the above will work.
Admin
Updated on July 09, 2022Comments
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Admin almost 2 years
I have commands in a bash script that are similar to this:
eval "( java -classpath ./ $classname ${arguments[@]} $redirection_options $file )" & pid=$!
However if I do a
ps $pid
it shows the main script process instead of the process of the java program.It obtains the correct process when I omit the eval, but in order to get some of the complicated arguments to work correctly I need to use it.
Any idea of how I can get the PID of the java program when it's executed within an eval command?
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barti_ddu over 13 yearsYes, this is it :)
EXPR="java -jar test.jar &"; eval $EXPR; echo $!
should do -
Mike Q over 10 yearsFYI: I noticed this works from a terminal but if you have a script with an icon on the desktop, it doesn't work.
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Roel Van de Paar over 3 yearsMake sure to add
"
double quotes around the expression being evaluated, and also make sure to add the&
inside those double quotes, just before the final double quote.