Is there a way to instantiate objects from a string holding their class name?

91,881

Solution 1

Nope, there is none, unless you do the mapping yourself. C++ has no mechanism to create objects whose types are determined at runtime. You can use a map to do that mapping yourself, though:

template<typename T> Base * createInstance() { return new T; }

typedef std::map<std::string, Base*(*)()> map_type;

map_type map;
map["DerivedA"] = &createInstance<DerivedA>;
map["DerivedB"] = &createInstance<DerivedB>;

And then you can do

return map[some_string]();

Getting a new instance. Another idea is to have the types register themself:

// in base.hpp:
template<typename T> Base * createT() { return new T; }

struct BaseFactory {
    typedef std::map<std::string, Base*(*)()> map_type;

    static Base * createInstance(std::string const& s) {
        map_type::iterator it = getMap()->find(s);
        if(it == getMap()->end())
            return 0;
        return it->second();
    }

protected:
    static map_type * getMap() {
        // never delete'ed. (exist until program termination)
        // because we can't guarantee correct destruction order 
        if(!map) { map = new map_type; } 
        return map; 
    }

private:
    static map_type * map;
};

template<typename T>
struct DerivedRegister : BaseFactory { 
    DerivedRegister(std::string const& s) { 
        getMap()->insert(std::make_pair(s, &createT<T>));
    }
};

// in derivedb.hpp
class DerivedB {
    ...;
private:
    static DerivedRegister<DerivedB> reg;
};

// in derivedb.cpp:
DerivedRegister<DerivedB> DerivedB::reg("DerivedB");

You could decide to create a macro for the registration

#define REGISTER_DEC_TYPE(NAME) \
    static DerivedRegister<NAME> reg

#define REGISTER_DEF_TYPE(NAME) \
    DerivedRegister<NAME> NAME::reg(#NAME)

I'm sure there are better names for those two though. Another thing which probably makes sense to use here is shared_ptr.

If you have a set of unrelated types that have no common base-class, you can give the function pointer a return type of boost::variant<A, B, C, D, ...> instead. Like if you have a class Foo, Bar and Baz, it looks like this:

typedef boost::variant<Foo, Bar, Baz> variant_type;
template<typename T> variant_type createInstance() { 
    return variant_type(T()); 
}

typedef std::map<std::string, variant_type (*)()> map_type;

A boost::variant is like an union. It knows which type is stored in it by looking what object was used for initializing or assigning to it. Have a look at its documentation here. Finally, the use of a raw function pointer is also a bit oldish. Modern C++ code should be decoupled from specific functions / types. You may want to look into Boost.Function to look for a better way. It would look like this then (the map):

typedef std::map<std::string, boost::function<variant_type()> > map_type;

std::function will be available in the next version of C++ too, including std::shared_ptr.

Solution 2

No there isn't. My preferred solution to this problem is to create a dictionary which maps name to creation method. Classes that want to be created like this then register a creation method with the dictionary. This is discussed in some detail in the GoF patterns book.

Solution 3

The short answer is you can't. See these SO questions for why:

  1. Why does C++ not have reflection?
  2. How can I add reflection to a C++ application?

Solution 4

I have answered in another SO question about C++ factories. Please see there if a flexible factory is of interest. I try to describe an old way from ET++ to use macros which has worked great for me.

ET++ was a project to port old MacApp to C++ and X11. In the effort of it Eric Gamma etc started to think about Design Patterns

Solution 5

boost::functional has a factory template which is quite flexible: http://www.boost.org/doc/libs/1_54_0/libs/functional/factory/doc/html/index.html

My preference though is to generate wrapper classes which hide the mapping and object creation mechanism. The common scenario I encounter is the need to map different derived classes of some base class to keys, where the derived classes all have a common constructor signature available. Here is the solution I've come up with so far.

#ifndef GENERIC_FACTORY_HPP_INCLUDED

//BOOST_PP_IS_ITERATING is defined when we are iterating over this header file.
#ifndef BOOST_PP_IS_ITERATING

    //Included headers.
    #include <unordered_map>
    #include <functional>
    #include <boost/preprocessor/iteration/iterate.hpp>
    #include <boost/preprocessor/repetition.hpp>

    //The GENERIC_FACTORY_MAX_ARITY directive controls the number of factory classes which will be generated.
    #ifndef GENERIC_FACTORY_MAX_ARITY
        #define GENERIC_FACTORY_MAX_ARITY 10
    #endif

    //This macro magic generates GENERIC_FACTORY_MAX_ARITY + 1 versions of the GenericFactory class.
    //Each class generated will have a suffix of the number of parameters taken by the derived type constructors.
    #define BOOST_PP_FILENAME_1 "GenericFactory.hpp"
    #define BOOST_PP_ITERATION_LIMITS (0,GENERIC_FACTORY_MAX_ARITY)
    #include BOOST_PP_ITERATE()

    #define GENERIC_FACTORY_HPP_INCLUDED

#else

    #define N BOOST_PP_ITERATION() //This is the Nth iteration of the header file.
    #define GENERIC_FACTORY_APPEND_PLACEHOLDER(z, current, last) BOOST_PP_COMMA() BOOST_PP_CAT(std::placeholders::_, BOOST_PP_ADD(current, 1))

    //This is the class which we are generating multiple times
    template <class KeyType, class BasePointerType BOOST_PP_ENUM_TRAILING_PARAMS(N, typename T)>
    class BOOST_PP_CAT(GenericFactory_, N)
    {
        public:
            typedef BasePointerType result_type;

        public:
            virtual ~BOOST_PP_CAT(GenericFactory_, N)() {}

            //Registers a derived type against a particular key.
            template <class DerivedType>
            void Register(const KeyType& key)
            {
                m_creatorMap[key] = std::bind(&BOOST_PP_CAT(GenericFactory_, N)::CreateImpl<DerivedType>, this BOOST_PP_REPEAT(N, GENERIC_FACTORY_APPEND_PLACEHOLDER, N));
            }

            //Deregisters an existing registration.
            bool Deregister(const KeyType& key)
            {
                return (m_creatorMap.erase(key) == 1);
            }

            //Returns true if the key is registered in this factory, false otherwise.
            bool IsCreatable(const KeyType& key) const
            {
                return (m_creatorMap.count(key) != 0);
            }

            //Creates the derived type associated with key. Throws std::out_of_range if key not found.
            BasePointerType Create(const KeyType& key BOOST_PP_ENUM_TRAILING_BINARY_PARAMS(N,const T,& a)) const
            {
                return m_creatorMap.at(key)(BOOST_PP_ENUM_PARAMS(N,a));
            }

        private:
            //This method performs the creation of the derived type object on the heap.
            template <class DerivedType>
            BasePointerType CreateImpl(BOOST_PP_ENUM_BINARY_PARAMS(N,const T,& a))
            {
                BasePointerType pNewObject(new DerivedType(BOOST_PP_ENUM_PARAMS(N,a)));
                return pNewObject;
            }

        private:
            typedef std::function<BasePointerType (BOOST_PP_ENUM_BINARY_PARAMS(N,const T,& BOOST_PP_INTERCEPT))> CreatorFuncType;
            typedef std::unordered_map<KeyType, CreatorFuncType> CreatorMapType;
            CreatorMapType m_creatorMap;
    };

    #undef N
    #undef GENERIC_FACTORY_APPEND_PLACEHOLDER

#endif // defined(BOOST_PP_IS_ITERATING)
#endif // include guard

I am generally opposed to heavy macro use, but I've made an exception here. The above code generates GENERIC_FACTORY_MAX_ARITY + 1 versions of a class named GenericFactory_N, for each N between 0 and GENERIC_FACTORY_MAX_ARITY inclusive.

Using the generated class templates is easy. Suppose you want a factory to create BaseClass derived objects using a string mapping. Each of the derived objects take 3 integers as constructor parameters.

#include "GenericFactory.hpp"

typedef GenericFactory_3<std::string, std::shared_ptr<BaseClass>, int, int int> factory_type;

factory_type factory;
factory.Register<DerivedClass1>("DerivedType1");
factory.Register<DerivedClass2>("DerivedType2");
factory.Register<DerivedClass3>("DerivedType3");

factory_type::result_type someNewObject1 = factory.Create("DerivedType2", 1, 2, 3);
factory_type::result_type someNewObject2 = factory.Create("DerivedType1", 4, 5, 6);

The GenericFactory_N class destructor is virtual to allow the following.

class SomeBaseFactory : public GenericFactory_2<int, BaseType*, std::string, bool>
{
    public:
        SomeBaseFactory() : GenericFactory_2()
        {
            Register<SomeDerived1>(1);
            Register<SomeDerived2>(2);
        }
}; 

SomeBaseFactory factory;
SomeBaseFactory::result_type someObject = factory.Create(1, "Hi", true);
delete someObject;

Note that this line of the generic factory generator macro

#define BOOST_PP_FILENAME_1 "GenericFactory.hpp"

Assumes the generic factory header file is named GenericFactory.hpp

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Gal Goldman
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Gal Goldman

Education: M.Sc. in Mathematics B.Sc. in Mathematics &amp; Computer Science Occupation: Current: - CPU Product Development Team Leader | Program Manager at Intel Corporation Past: - Software Project leader at Intel Corporation - Software engineer at Elbit Systems LTD. Experience: Languages: C++/Qt/C#/.NET/C/ADA/Perl Platforms: UNIX/Linux/Windows

Updated on May 09, 2022

Comments

  • Gal Goldman
    Gal Goldman about 2 years

    I have a file: Base.h

    class Base;
    class DerivedA : public Base;
    class DerivedB : public Base;
    
    /*etc...*/
    

    and another file: BaseFactory.h

    #include "Base.h"
    
    class BaseFactory
    {
    public:
      BaseFactory(const string &sClassName){msClassName = sClassName;};
    
      Base * Create()
      {
        if(msClassName == "DerivedA")
        {
          return new DerivedA();
        }
        else if(msClassName == "DerivedB")
        {
          return new DerivedB();
        }
        else if(/*etc...*/)
        {
          /*etc...*/
        }
      };
    private:
      string msClassName;
    };
    
    /*etc.*/
    

    Is there a way to somehow convert this string to an actual type (class), so that BaseFactory wouldn't have to know all the possible Derived classes, and have if() for each one of them? Can I produce a class from this string?

    I think this can be done in C# through Reflection. Is there something similar in C++?

    • smerlin
      smerlin over 14 years
      its partially possible with C++0x and variadic templates..
  • dirkgently
    dirkgently over 15 years
    So, are you saying you won't need different class definitions for a Bus and a Car since they are both Vehicles? However, if you do, adding another line shouldn't really be a problem :) The map approach has the same problem -- you update the map contents. The macro thingy works for trivial classes.
  • Gal Goldman
    Gal Goldman over 15 years
    I am saying that in order to CREATE a Bus or a Car in my case, I don't need different definitions, otherwise the Factory design pattern would never be in use. My goal was to have the factory as stupid as it can be. But I see here that there's no escape :-)
  • Gal Goldman
    Gal Goldman over 15 years
    Loved the idea that the derived classes will register themselves. It's exactly what I was looking for, a way to remove the hard-coded knowledge of which derived classes exist from the factory.
  • Spencer Rose
    Spencer Rose almost 13 years
    Originally posted by somedave in another question, this code fails on VS2010 with ambiguous template errors because of make_pair. To fix, change make_pair to std::pair<std::string,Base*()()> and it should fix those errors. I also got some linking errors which were fixed by adding BaseFactory::map_type BaseFactory::map = new map_type(); to base.cpp
  • Poul K. Sørensen
    Poul K. Sørensen over 12 years
    I am having problems implementing this, using Vs2010 and using std::pair instead of make_pair. When compiling i get link errors. Adding my counterpart to static DerivedRegister<DerivedB> reg, static MouseFeatureRegister mouse_reg; compiles fine. but when adding MouseFeatureRegister CvMaskOverlay::mouse_reg("Masking - Polygon"); i do get some link errors. The idea are only for subclasses to register a string in a map with an increasing counter assigned to it. so not using templates
  • musiphil
    musiphil over 11 years
    How do you ensure that DerivedB::reg is actually initialized? My understanding is that it may not be constructed at all if no function or object defined in the translation unit derivedb.cpp, as per 3.6.2.
  • josaphatv
    josaphatv about 10 years
    Anybody care to identify which pattern this is, rather than just point at the book?
  • jiggunjer
    jiggunjer about 9 years
    I think he is referring to the registry pattern.
  • Grimeh
    Grimeh almost 9 years
    For those reading this answer now, I believe the answer is referring to using the Factory pattern, an implementation that uses a dictionary to determine which class to instantiate.
  • Admin
    Admin over 8 years
    And then you can do return map[some_string](); is no good if some_string does not exist
  • Sven
    Sven almost 8 years
    Love the self-registration. To compile though I needed a BaseFactory::map_type * BaseFactory::map = NULL; in my cpp file. Without this, the linker complained about unknown symbol map.
  • Tomasito665
    Tomasito665 over 7 years
    Unfortunately, this doesn't work. As musiphil already pointed out, DerivedB::reg is not initialized if none of its functions or instances is defined in the translation unit derivedb.cpp. That means that the class is not registred untill it is actually instantited. Does anybody know a workaround for that?
  • ihadanny
    ihadanny over 7 years
    how is it possible so many people voted up this solution when @musiphil is right and it just doesn't work??
  • Johannes Schaub - litb
    Johannes Schaub - litb over 7 years
    @ihadanny just add a dummy use and you are fine. It's pseudo code. As others have pointed out, definition of BaseFactory::map is missing aswell. For a workaround for the static data member issue, see stackoverflow.com/questions/401621/…
  • Hayden
    Hayden over 5 years
    @JohannesSchaub-litb I've used this solution a few times with self registering classes. I'm now struggling to make the BaseFactory::createInstance method take any number of arguments. I have some object types that don't need any arguments, and some that need a file path and perhaps an additional boolean. I can modify createT to accept typename Args ...., but the reference added to the map knows nothing about that. Anyone successfully done that? Maybe some std::function object that can take and pass variadic args
  • Hayden
    Hayden over 5 years
    @JohannesSchaub-litb I was able to figure it out. I used a map to a std::variant of std::function objects, and had to declare the prototype for each new constructor for the variant. Then passed Args... through the templates from the AutoRegister<T, arg1, arg2...> down to createT(Args... args). Might not use it at all though, since it's probably cleaner to let the Factory handle the extra initialization steps and keep all constructors as default, or even private.
  • Remy Lebeau
    Remy Lebeau almost 3 years
    On a side note: static map_type * getMap() really should not use new, that is not thread-safe in this context. A static local variable would make more sense, eg: static map_type * getMap() { static map_type map; return &map; } Or better: static map_type & getMap() { static map_type map; return map; }
  • Admin
    Admin over 2 years
    As it’s currently written, your answer is unclear. Please edit to add additional details that will help others understand how this addresses the question asked. You can find more information on how to write good answers in the help center.