Java ArrayList Contain always return false although it contain the same value

22,611

Solution 1

You need to override the equals method herited from the Object class (and hence also hashCode to respect the contract, see Why do I need to override the equals and hashCode methods in Java? ) in your Hole class.

Returns true if this list contains the specified element. More formally, returns true if and only if this list contains at least one element e such that (o==null ? e==null : o.equals(e)).

Basically the default equals implementation is an == comparison between the two objects

public boolean equals(Object obj) {
   return (this == obj);
}

Since you created two different objects, while they have the same value as attributes they're two distincts objects and hence this == obj returns false.

If you did :

Hole a = new Hole(0,1);
leftFlowInnerHole.add(a);
System.out.print(leftFlowInnerHole.contains(a));

You'll see that it outputs true.

Solution 2

You should overide the equals method of the Hole class:

@Override
public boolean equals(Object obj) {

if (obj == this) {
    return true;
}

if (!(obj instanceof Hole)) {
    return false;
}

Hole other = (Hole) obj;

return a == other.a && b == other.b;
}

Solution 3

contains() method checks the equal() method on Object while checking .

You have to ovveride equals method in order to make it work.

public boolean contains(Object o)

Returns true if this list contains the specified element. More formally, returns true if and only if this list contains at least one element e such that (o==null ? e==null : o.equals(e)).

Edit:

If you not ovveriding equals method, Then default Object equals method executes and, as per docs of Equals method

The equals method for class Object implements the most discriminating possible equivalence relation on objects; that is, for any non-null reference values x and y, this method returns true if and only if x and y refer to the same object (x == y has the value true).

So your userInputHole == leftFlowInnerHole is always false as they are pointing to different instances.

Hence to avoid the default implementation ,you just ovveride that equals in yout class and provide your implementation.

An efficient equals(Object o) implementation

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Shan Markus
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Shan Markus

Updated on March 26, 2020

Comments

  • Shan Markus
    Shan Markus about 4 years

    This is my Hole Class

    class Hole {
    
    public  int a;
    public  int b;
    
    Hole(int a, int b) {
        this.a = a;
        this.b = b;
    }
    

    So i adding an ArrayList that contain several several hole

    public void checkPathLoop(int x, int y) {
            //rough code
    
            ArrayList<Hole> leftFlowInnerHole = new ArrayList<>();
    
    
            //left holes rules
            leftFlowInnerHole.add(new Hole(0, 1));
            leftFlowInnerHole.add(new Hole(1, 5));
            leftFlowInnerHole.add(new Hole(5, 4));
            leftFlowInnerHole.add(new Hole(0, 4));
    

    when i add

    Hole userInputHole = new Hole(0,1);
    System.out.print(leftFlowInnerHole.contain(userInputHole));
    

    it always return false !! it suppose to return true.

    Is there anything i miss ??

    Thank you in advance

  • kosa
    kosa over 10 years
    Isn't equals() default implementation execute in this case?
  • kosa
    kosa over 10 years
    Why false (because default implementation uses == for comparison)? that is the point missing in answer.