java Runtime.exec to run shell script - cannot open file

10,694

Solution 1

Use a ProcessBuilder and set the working directory of the process to the directory where your script actually is:

final ProcessBuilder pb = new ProcessBuilder("/bin/sh", "script.sh", "whatever",
    "arguments", "go", "here");
pb.directory(new File("/path/to/directory"));
// redirect stdout, stderr, etc
final Process p = pb.start();

See the ProcessBuilder javadoc. It contains an example of what you can do. Runtime.exec() is passé :p

Solution 2

sh is unable to find the build.sh script. To fix this you can provide the full path to build.sh.

Solution 3

Try this:

 String[] cmd = {"sh build.sh", "/Path/to my/shfile"};

and better to use ProcessBuilder

ProcessBuilder pb = new ProcessBuilder("sh build.sh", "/Path/to my/shfile"); 

Solution 4

The problem is that the "sh" command is unable to resolving the relative path "build.sh" to an absolute path. The most likely explanation is that "build.sh" is not in the current directory when you launch the command.

Assuming that "/Path/to my/sh file" string is the path to the "build.sh" file, you need to run it like this:

String[] cmd = {"/bin/sh",  "/Path/to my/sh file/build.sh"};
try {
    Process proc = Runtime.getRuntime().exec(cmd);
    ...

(.... or the equivalent using ProcessBuilder)

On the other hand, if the "/Path/to my/sh file" string is supposed to be an argument to the "build.sh" script, then you need to run it like this:

String[] cmd = {"/bin/sh", "/some/dir/build.sh", "/Path/to my/sh file"};
try {
    Process proc = Runtime.getRuntime().exec(cmd);

@fge's answer gives an alternative approach. He is setting the current directory for the child process before it is launched. That is the correct solution for your updated Question.

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user1400538
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user1400538

Updated on June 05, 2022

Comments

  • user1400538
    user1400538 almost 2 years

    I am using Runtime.getRuntime().exec() to run a shell script from java code.

        String[] cmd = {"sh",  "build.sh", "/Path/to my/sh file"};
        try{
            Process proc = Runtime.getRuntime().exec( cmd );
        }
        catch(Exception e){
            System.out.println("Exception is:"+e);
        }
    

    It gives me the following output in console:

    sh: Can't open build.sh
    

    Am I following some wrong approach here? Cannot make out why his happens.

    EDIT

    Based on the comment here, I have modified the String[] cmd = {"sh", "build.sh", "/Path/to my/sh file"}; to String[] cmd = {"sh", "/Path/to my/sh file/build.sh", "/Path/to my/sh file"}; . Now the problem is this script need to be executed from a particular path. When I execute this script from command prompt, I first change the directory to that path and execute it. How should I modify this code?