Label width in tkinter

Question

I'm writing an app with tkinter and I am trying to put several labels in a frame... Unfortunately,

windowTitle=Label(... width=100)

and

windowFrame=Frame(... width=100)

are very different widths...

So far, I use this code:

windowFrame=Frame(root,borderwidth=3,relief=SOLID,width=xres/2,height=yres/2)
windowFrame.place(x=xres/2-160,y=yres/2-80)
windowTitle=Label(windowFrame,background="#ffa0a0",text=title)
windowTitle.place(x=0,y=0)
windowContent=Label(windowFrame,text=content,justify="left")
windowContent.place(x=8,y=32)

...

#xres is screen width
#yres is screen height

For some reason, setting label width doesn't set width correctly, or doesn't use pixels as measurement units... So, is there a way to place windowTitle widget in such way that it adapts to the lenght of the frame, or to set label width in pixels?

Solution

height and width define the size of the label in text units when it contains text. Follow @Elchonon Edelson's advice and set size of frame + one small trick:

from tkinter import *
root = Tk()

def make_label(master, x, y, h, w, *args, **kwargs):
    f = Frame(master, height=h, width=w)
    f.pack_propagate(0) # don't shrink
    f.place(x=x, y=y)
    label = Label(f, *args, **kwargs)
    label.pack(fill=BOTH, expand=1)
    return label

make_label(root, 10, 10, 10, 40, text='xxx', background='red')
make_label(root, 30, 40, 10, 30, text='xxx', background='blue')

root.mainloop()

Comments

[Mirac7]

Not, really what I had in mind... However, fill=X should serve me nicely... Thanks...