List file range with UNIX wildcards
Solution 1
You can use brace expansion:
ls mjk00{25..50}.fits
Leading zeros can be included if necessary:
ls mjk0{000..149}.fits
Solution 2
You could use a regex with grep. I'm not a regex guru. The following returns the pattern with the numbers betweeen 25-50:
ls | sort -n | grep -E 'mjk00([2][5-9]|[3-4][0-9]|[5][0]).fits'
I don't know if it is possible and how eventually generalize this with grep.
Solution 3
Not directly, but you can use multiple glob patterns:
ls mjk002[56789].fits mjk00[34]?.fits
It's not exactly what you are looking for, but it's the closest thing that glob patterns offer, and it is certainly better than typing each fileystem. At least the number of patterns you will need per numerical range is bounded by the log of the numerical endpoints of the range.
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Admin
Updated on September 18, 2022Comments
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Admin over 1 year
Say for example I have the following files in my working directory: mjk0001.fits, mjk0002.fits, ... numerically increasing all the way to mjk9999.fits.
Is there a way to use UNIX wildcards to list or operate on a sequential group of them? For example, if I need to run a process on 0025 through 0050, what format would I use?
I have tried the following but have had no success:
ls *[25-50].fits ls mjk00[25-50].fits ls mjk[0025-0050]* ls *[0025-0050]*
Thanks in advance everyone, MK
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Brent Bradburn about 7 yearsUsing this syntax, you can also specify a step value:
{25..50..2}
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Brent Bradburn over 6 yearsIf you want to separate the results of brace expansion, you can use a for loop:
for i in {025..050} ; do ... ; done