Mapping XML to classes in c#
14,863
Solution 1
If you're locked into this XML schema, this will serialize or de-serialize your XML and object data:
using System;
using System.IO;
using System.Xml;
using System.Xml.Serialization;
public class ProductsViewModel
{
public string Xml { get; set; }
public Product Poco { get; set; }
public ProductsViewModel()
{
Xml = Serialize(new Product());
Poco = (Product)Deserialize(Xml, typeof(Product));
}
public class Price
{
[XmlAttribute(AttributeName = "price")]
public int Value { get; set; }
}
[XmlRoot(ElementName = "products")]
public class Product
{
[XmlAttribute(AttributeName = "grand-total")]
public int GrandTotal { get; set; }
[XmlElement(ElementName = "one")]
public Price OnePrice { get; set; }
[XmlElement(ElementName = "two")]
public Price TwoPrice { get; set; }
[XmlElement(ElementName = "tree")]
public Price ThreePrice { get; set; }
public Product()
{
GrandTotal = 100;
OnePrice = new Price { Value = 50 };
TwoPrice = new Price { Value = 20 };
ThreePrice = new Price { Value = 30 };
}
}
private string Serialize(object obj)
{
var serializer = new XmlSerializer(obj.GetType());
using (var stringWriter = new StringWriter())
{
serializer.Serialize(stringWriter, obj);
return stringWriter.ToString();
}
}
private object Deserialize(string serializedObj, Type type)
{
var serializer = new XmlSerializer(type);
using (var stringReader = new StringReader(serializedObj))
using (var xmlTextReader = new XmlTextReader(stringReader))
{
return serializer.Deserialize(xmlTextReader);
}
}
}
Solution 2
Assuming the POCO is what you can modify:
[Serializable]
[XmlRoot("one")]
public class OnePrice
{
[XmlAttribute("price")]
public int price { get; set; }
}
[Serializable]
[XmlRoot("two")]
public class TwoPrice
{
[XmlAttribute("price")]
public int price { get; set; }
}
[Serializable]
[XmlRoot("three")]
public class ThreePrice
{
[XmlAttribute("price")]
public int price { get; set; }
}
[Serializable]
[XmlRoot("products")]
public class Product
{
[XmlAttribute("grand-total")]
public int GrandTotal { get; set; }
[XmlElement("one")]
public OnePrice OnePrice { get; set; }
[XmlElement("two")]
public TwoPrice TwoPrice { get; set; }
[XmlElement("three")]
public ThreePrice ThreePrice { get; set; }
}
If you can modify the XML, you can do it a little more easily by not using attributes and just sticking to elements (at least for One, Two, and Three).
Author by
Jay
Updated on June 04, 2022Comments
-
Jay almost 2 years
I'm looking to map multiple XML attributes in nested elements into a single POCO class using the XmlSerializer object.
XML
<products grand-total="100"> <one price="50" /> <two price="20" /> <tree price="30" /> </products>
POCO
public class Product { public int GrandTotal { get; set; } public int OnePrice { get; set; } public int TwoPrice { get; set; } public int ThreePrice { get; set; } }
C#
var doc = XDocument.Load("XmlDoc.xml"); var serializer = new XmlSerializer(typeof(Product)); var reader = doc.Root.CreateReader(); var temp = (Product)serializer.Deserialize(reader);
It would be awesome if anyone knows how I can do this.
Thanks.