NameError: name 'self' is not defined, even though it is?
67,582
The for
loop is indented incorrectly resulting in it being outside that method's scope but inside the class' scope. This in turn means that self
is not defined.
Python does interpret that loop code in the scope of the class, but without an instance of the object. Sample malformed code:
class Simple(object):
def __init__(self, a):
self.a = a
print("Here we go!")
for i in xrange(self.a):
print(i)
Traceback
$ python simple.py
Here we go!
Traceback (most recent call last):
File "simple.py", line 4, in <module>
class Simple(object):
File "simple.py", line 9, in Simple
for i in xrange(self.a):
NameError: name 'self' is not defined
Author by
Paul Bentham
Updated on June 17, 2020Comments
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Paul Bentham almost 4 years
Can anyone helps me understand why this is this giving me an error? The error being "NameError: name 'self' is not defined". I have a similar class higher up in my code and that works fine?
I'm using 'xlrd' and team is a reference to a workbook.sheet_by_name.
class Rollout: def __init__(self, team, name): self.team = team self.name = name self.jobs = {} self.start_row = 1 self.last_row = self.team.nrows for i in range(self.start_row,self.last_row): try: self.jobs[i-1] = [str(self.team.cell_value(i,0)).upper(), \ str(self.team.cell_value(i,1)).upper(), \ str(self.team.cell_value(i,2)).upper(), \ str(self.team.cell_value(i,3)).upper(), \ str(xlrd.xldate_as_tuple(self.team.cell_value(i,4),0)[3]), \ str(self.team.cell_value(i,5)).upper(), \ str(self.team.cell_value(i,6)).upper()] except ValueError: print "It look's like one of your 'time' cells is incorrect!" self.jobs[i-1] = [str(self.team.cell_value(i,0)).upper(), \ str(self.team.cell_value(i,1)).upper(), \ str(self.team.cell_value(i,2)).upper(), \ str(self.team.cell_value(i,3)).upper(), \ "missing", \ str(self.team.cell_value(i,5)).upper(), \ str(self.team.cell_value(i,6)).upper()]
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Silas Ray over 10 yearsPython interprets the loop code in the execution scope of the
class
body. Whatever ends up in the namespace after executing the code in the class scope becomes the attribute dictionary of the class object. Were there not aNameError
because ofself
,Simple.i
would end up being whateveri
ended up set to after the loop completed. -
mishsx almost 4 yearsThis does not answer the OP's question. You're explaining him what a class is which is not what has been asked. Please remove/ edit your answer accordingly
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Dominux over 3 yearsMan, it is another problem, and a difference between difficulty of yours one and presented one is like between the sky and the Earth